Answer:
thus next three terms are -3,-5,-7
Step-by-step explanation:
a=1
first find d
-1-1
-2
then a.p= a,a+d,a+2d,a+3d,a+4d
=1,1-2,1+2×-2,1+3×-2,1+4×-2
=1,-1,1-4,1-6,1-8
=1,-1,-3,-5,-7
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The probability of that occurring is 0%. There are 6 sides in a typical dice, which means the probability of rolling a 2 is 1/6th. (1/6)^1000 will give you the probability of rolling a 2 exactly 1000 times. (1/6)^1000 equates to 0%.
Hi student, let me help you out! :)
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We are asked to find the two integers, given that they are consecutive, and their sum is 65.

- Consecutive integers are right next to each other, like 12 and 13. or 65 and 66.
Let the first integer be x, and let the second integer be x+1.
Their sum is 65. Let's set up our equation:

Combine like terms:

Subtract 1 from both sides of the equal sign:

Divide both sides by 2:

To find the second integer, subtract the first integer from the sum of the two integers:


The integers are: 33 and 32.
Hope it helps you out! :D
Ask in comments if any queries arise.
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F-1:
y=x+9
y-9=x
x-9=f-1
f-1(14)=14-9=5 f-1(5)=5-9=-4 f-1(-5)=-5-9=-14 f-1(25)=25-9=16
f(14)=14+9=24 f(5)=5+9=14 f(-5)=9-5=4 f(25)=25+9=34
ANSWER
The correct answer is C
.
<u>EXPLANATION</u>
We have

and
.
We solve the two equation simultaneously by elimination method. We need to be smart and eliminate y, since we are looking for
.
We first multiply equation (2) by 2
.
We add equation (3) and (1).
.
Dividing through by 6 gives
.