Answer:
H (x= -3 , y=5)
I (x=8 , y=2)
J (x= -3 , y= -5)
D is the distance between the 2 points so just plug in the x and y cords of each of the corresponding points
so for (HI)
you plug in 2 on the red x
and 8 on the red y
then -3 in the blue x
and 5 in the blue y
$10.71
Explanation
Step 1
you can easily solve this by using a rule of three.
Let
x represents the money Eileen will pay if her bag weighs 63 pounds
the proportion is the same
then
Step 2
solve for x
I hope this helps you
Step-by-step explanation:
N=8
that is the answer
I am sure
Step-by-step explanation:
Let's start with solving for line L using slope-intercept form (y=mx+b)
We can see that the y-intercept is 4, and the slope is rise/run. From point (5,2) to (0,5), the rise is 2, and the run is -5 (it goes backwards 5).
Using this, we can form our equation for Line L: y = -2/5x + 4
Now let's solve for Line M.
There is something very important to notice before we jump into this. Both of these lines (Line L and M) are parallel (they never touch) and therefore will contain the same slope as each other (-2/5). The y-intercept for this equation we can see is -1, as the line touches (0,-1). Now lets form our equation;
Line M: y = -2/5+4
Solving a system of equation means to find two (or more) line's interceptions on a graph (where they meet/touch). Because both of these lines are parallel and never touch each other, there is no definite answer. Therefore our answer is No Solutions.
If a department has 11 male employees and 17 female employees, then 198968 different committees of 6 members are possible with the condition that the committee has strictly more female employees than male.
As per the question statement, a department has 11 male employees and 17 female employees.
We re required to calculate the total number different committees that can be formed with 6 members strictly having more female employees than male.
Now for committee of 6 members to have more women than men, there can be two combinations:
(4 women and 2 men)
Or, (5 Women and 1 man).
That is, we will need to calculate the number of combinations we can have by selecting 4 female employees from a group of 17 and 2 Male employees from a group of 11 and the number of combinations we can have by selecting 5 female employees from a group of 17 and 1 Male employee from a group of 11 and add up the two number of combinations to obtain our required answer.
Then comes the most important thing to know to be able to solve this question, i.e., the formula to calculate combinations, which goes as
Therefore, the total number different committees that can be formed with 6 members strictly having more female employees than male is
- combination(s): In mathematics, a combination is a way of selecting items from a collection or set, where the order of selection does not matter, i.e., for example, we have a set of three numbers X, Y and Z and then, in how many ways can we select two numbers from each set, is defined by combination.
To learn more about Combinations, click on the link below.brainly.com/question/8044761
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