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alexandr1967 [171]
4 years ago
12

A tile pattern on a wall is made up of two identical parallelograms and three identical triangles. Each parallelogram has a base

of 14 in. and a height of 10 in. The height of the entire pattern is 18 in. What is the area?
PLZZ HELP

Mathematics
2 answers:
stellarik [79]4 years ago
8 0
It would have been better if a figure come with your question but I will just imagine how the pattern looks like.

Automatically, the area of the two parallelograms is
(14) (10) + (14)(10) = 280 square inches
The are of the three triangles assuming that they are on top of the parallelogram is
3 (1/2) (18 - 10)(7) = 84 sq. inches

The total area is
280 + 84 = 364 sq. inches
gtnhenbr [62]4 years ago
8 0

Answer:

The answer to this question is 488 in^2

Step-by-step explanation:

I just took the test. There is a link to my step by step explanation in this.

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\bf \begin{cases} x^2+y^2=400\\ \boxed{y}=x-28 \end{cases}\qquad \stackrel{\textit{substituting on the 1st equation}}{x^2+\left( \boxed{x-28} \right)^2=400} \\\\\\ x^2+(x^2-56x+28^2)=400\implies x^2+x^2-56x+28^2=400 \\\\\\ 2x^2-56x+784=400\implies 2x^2-56x+384=0 \\\\\\ 2(x^2-28x+192)=0\implies x^2-28x+192=0 \\\\\\ (x-16)(x-12)=0\implies x = \begin{cases} 16\\ 12 \end{cases}

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