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4 years ago

Factor x2 + 4x + 4! Please help!

Mathematics

2 answers:

Luden [163]4 years ago

5 0

This is a whole squared equation. So, it is (x+2)^2.
If you check it, you get x2 + 4x + 4

Hope this helps!

Mrrafil [7]4 years ago

3 0

The answer should be (x + 2)^2 because when factoring using grouping, you can rid of two x's from the first two terms, and you can factor 4 into 2 * 2. Factoring the first two terms rids of the first and leaves two x's in the second. You can check if i'm right by multiplying (x + 2) (x + 2). This should give x^2 + 2x + 2x + 4. Simplyify this into x^2 + 4x + 4 by combining like terms. Hope this helps.

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3 years ago

A force F=-2i+j+k acts at point A(1,5,1) on a solid which is free to turn about a fixed point Q(-1,2,1). Find the torque exerted

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The torque exerted by the force on the body is $\vec \tau = 3\,\hat{i}-2\,\hat{j} + 8\,\hat{k}$ .

Vectorially speaking, the torque exerted ( $\vec \tau$ ) by the force on the body ( $\vec F$ ) is resulted from this expression:

$\vec \tau = \vec r_{QA} \times \vec F$ (1)

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$\vec r_{QA}$ - Vector distance between points A and Q.
$\vec F$ - Vector force exerted at point A.

If we know that $\vec r_{QA} = (2, 3, 0)$ and $\vec F = (-2, 1, 1)$ , then the torque is:

$\vec \tau = \left|\begin{array}{ccc}\hat{i}&\hat{j}&\hat{k}\\2&3&0\\-2&1&1\end{array}\right|$

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The torque exerted by the force on the body is $\vec \tau = 3\,\hat{i}-2\,\hat{j} + 8\,\hat{k}$ .

To learn more on torque, we kindly invite to check this verified question: brainly.com/question/3388202

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