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vovikov84 [41]
2 years ago
11

Can you help with this question? I am kinda stuck.

Mathematics
1 answer:
ruslelena [56]2 years ago
4 0

Answer:

  • 29400 cm²

Step-by-step explanation:

The cube has 6 equal faces.

<u>Total surface area:</u>

  • S = 6a²
  • S = 6*(0.7 m)² = 6*(70 cm) ² = 29400 cm²
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Solve the following quadratic equation:
Advocard [28]

Answer:

-3.5 or -6

Step-by-step explanation:

2x^2+19x+40=-2

2x^2+19x+40+2=0

2x^2+19x+42=0

2x^2+(12+7)x+42=0

2x^2+12x+7x+42=0

2x(x+6)+7(x+6)=0

(x+6)(2x+7)=0

either,

x+6=0

x=-6

or,

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x=-7/2

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4 0
3 years ago
Can someone help me please​
Andrej [43]

Answer: is A

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
I NEED THIS ANSWER AAAAA
enyata [817]
The answer is 400 because 40.00*8.5 is 340.00. Add on the 60 dollar service charge and get 400.00.

Hope this helped :)
5 0
3 years ago
If the maximum acceleration that is tolerable for passengers in a subway train is 1.74 m/s2 and subway stations are located 930
Free_Kalibri [48]
Given that the subway stations are 930 m apart, the train have to be accerelated for half the distance and then decerelated for the rest of the distance.

Recall that the distance travelled by an object with an initial velocity, u, for a period of time, t, at an accereration, a, is given by
s=ut+ \frac{1}{2} at^2

But, we assume that the train accelerates from rest, thus
s=\frac{1}{2} at^2 \\  \\ \Rightarrow465=\frac{1}{2}(1.74)t^2 \\  \\ \Rightarrow t^2=534.48 \\  \\  \Rightarrow t=\sqrt{534.48}=23.12

The maximum speed is attained at half the center of the distance between subway stations (i.e. at distance = 465 m).

Thus, maximum speed = distance / time = 465 / 23.12 = 20.11 m/s.
6 0
3 years ago
A package of 5 pairs of insulated socks costs ​$26.45. What is the unit price of the pairs of socks​?
tigry1 [53]

Answer:

$5.29 per pair of socks

Step-by-step explanation:

26.45/5=5.29

3 0
2 years ago
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