Answer:
Ok, first in our series we can see two numbers in the Sigma, one bellow 0, and other above, 4.
This means that the value of k will go from 0 to 4, then all the numbers in the sum are:
(-1/2)^0 + (-1/2)^1 + (-1/2)^2 + (-1/2)^3 + (-1/2)^4
So we have 5 terms in our series.
b) to see the sign in each term, we must solve the powers, remember that:
(-1)^n is -1 if n is odd, and is equal to 1 if n is even, so we have:
(-1/2)^0 + (-1/2)^1 + (-1/2)^2 + (-1/2)^3 + (-1/2)^4
= 1 -1/2 + 1/4 - 1/8 + 1/16.
So the sign in each term of the series alternates.
4,5 is the answer I think
Answer:
Let's name the digit:
x- ones digit
y - tens digit
we know that x=y-2.
Now, y can be 6,7,8,9 (the number is between 60 and 100 (so depending on your understanding of "between", 0 is also possible. but then the number would have to have -2 as its ones digit, so in any case, it's not possible).
So the possibilities with x=y-2:
64
75
86
97
Out of those 64 and 86 are even, so they can't be prime.
75 has 5 in its ones number: it's divisible by 5.
so the correct answer is 97.
Step-by-step explanation:
Hope this helps!
1.SA=10e^2
rectacgular prism=2e*e*e
cube=e*e*e
the length given is 2e=5
so
SA=5e^2
SA=125cm2
