We know that
• The total is nine starters.
,
• The coach wants to choose three.
Given that the player cannot include repetition, we solve this problem as a combination because the order does not matter.

Where n = 9, and r = 3. Let's replace these values.

<h2>Hence, there are 84 different ways to choose the first three.</h2>
3x - y = 3.....3x - 3 = y
1/4x + 2/3(3x - 3) = -17/4
1/4x + 2x - 2 = -17/4 ...multiply everything by 4
x + 8x - 8 = -17
9x = -17 + 8
9x = - 9
x = -1
3x - y = 3
3(-1) - y = 3
-3 - y = 3
-3 - 3 = y
-6 = y
solution is (-1,-6)
Well, y=ny
2(y-1)=ny
(where ny is not-yellow)
You get y=2y-2 or y=2. You had two yellow birds and two other types.
Using th epythagorean theorem.
52^2-48^2= x^2
2704-2304= x^2
400=x^2
x=20
Final answer: D
Answer:
Step-by-step explanation:
This is permutation, since order matters. The formula for us is
₁₈P₅ =
which simplifies to
₁₈P₅ = 
The factorial of 13 cancels out on the top and bottom leaving you with
₁₈P₅ = 18 × 17 × 16 × 15 × 14
which comes to 1,028,160 ways
Another way to look at it is: the first 5 people of 18 finish and the others you don't care about. Once the first place person is first, there are only 4 of the 18 left to finish in second place. Then there are only 3 left to finish in third place, etc. So if we use that reasoning, we don't even need to use the formula, we can just say
18 * 17 * 16 * 15 * 14 and those are the first 5 people of 18 to finish.