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Phoenix [80]
3 years ago
14

Please help it would be very appreciated!!

Mathematics
2 answers:
Irina18 [472]3 years ago
8 0
Answer is 24.56 hope this helped
Leto [7]3 years ago
7 0

Answer:

answer is 24.56cm

perimeter of half/semi circle =  \pi r + 2r

<em>one semi circle semi circles perimeter:  </em>\pi<em>*2+2*2 =10.283cm, </em>

<em>for two semi circles= 2*10.283 =20.566cm</em>

without the line below for two semi circle: 20.566-4-4=12.566 cm

both da side of rectangle is 6cm+6cm=12cm

now add the 12.566+12=24.56cm

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Direction: True or False
Goshia [24]

Answer:

<u>False </u>Any three points are always coplanar

<u>False </u>Two points are always collinear

<u>False </u>Two planes intersect at a point

Read explanations, as the answer to these questions, is subjective.

Step-by-step explanation:

The definition of coplanar is; figures that exist on the same plane. Any three points might not always be colinear, as some points might exist on one plane, but other points could exist on other planes. To visualize this phenomenon, refer to the attached image. Two points could be on the red plane, but the third could be on the green. Therefore, while there are three points, not all of them exist on the same plane. However, another plane can be constructed to connect these points, bear in mind certain problems might specifically indicate that three points are not coplanar, therefore, the answer is false.

The definition of collinear is existing on the same line. This statement is a little subject, it can be both true and false depending on the way one looks at it. A line can be drawn to connect any two points, one only needs two points to determine a line. So technically two points are always collinear. However, it also depends on the circumstance. Certain geometry problems might specifically indicate that two points are not collinear. Thus, it really depends on the context. Therefore, the answer is technically false.

Two planes usually intersect on a line. To understand this, please refer to the image attached. Tehcnailly, if a corner of one plane intersects another, then one can state that the plane intersects on a point, but typically, planes intersect on lines. Therefore, technically the answer to this problem is false, as two planes usually intersect on a line.

Images credits: Geogebra

8 0
3 years ago
Read 2 more answers
Find the slope of (-4,3) (-3,4)
insens350 [35]

Answer:

y = x + 7

Step-by-step explanation:

3 0
2 years ago
Simplify each expression. (7x+x^4+x^3)-(6x-2x^3+8x^4)
aleksandrvk [35]
the answer is x + 3x^3 - 7x^4
8 0
3 years ago
A game field is 360 feet long. The practice field is 2/5 shorter than the practice field. How long is the game field?feet
vlabodo [156]

Answer:

The practice field is 144 feet long.

Step-by-step explanation:

360 x 2/5 = 144

(You would multiply these numbers NOT divide!)

To check my math:

2/5 = 0.4

144/360 = 0.4

By doing the above check, I know the two equations are the same. By seeing this I can know that the answer is correct.

4 0
3 years ago
The perimeter of equilateral triangle ABC is 81/3 centimeters, find the length of the radius and apothem.
MAXImum [283]

There is a typo error, the perimeter of equilateral triangle ABC is 81/√3 centimeters.

Answer:

Radius = OB= 27 cm

Apothem = 13.5 cm

A diagram is attached for reference.

Step-by-step explanation:

Given,

The perimeter of equilateral triangle ABC is 81/√3 centimeters.

Substituting this in the formula of perimeter of equilateral triangle =3\times\ side

3\times\ side =[tex]81\sqrt{3}

Side = \frac{81\sqrt{3} }{3} =27\sqrt{3} \ cm

Thus from the diagram , Side AB=BC=AC= 27\sqrt{3} \ cm

We know each angle of an equilateral triangle is 60°.

From the diagram, OB is an angle bisector.

Thus \angle OBC = 30°

Apothem is the line segment from the mid point of any side to the center the equilateral triangle.

Therefore considering ΔOBE, and applying tan function.

tan\theta =\frac{perpendicular}{base} \\tan\theta=\frac{OE}{BE} \\tan\theta=\frac{OE}{\frac{27\sqrt{3}}{2}  } \\tan30\times {\frac{27\sqrt{3} }{2} }= OE\\\frac{1}{\sqrt{3} } \times\frac{27\sqrt{3} }{2} =OE\\

Thus ,apothem  OE= 13.5 cm

Now for radius,

We consider ΔOBE

cos\theta=\frac{base}{hypotenuse} \\cos30= \frac{BE}{OB} \\Cos30 = \frac{\frac{27\sqrt{3} }{2}}{OB}  \\OB= \frac{\frac{27\sqrt{3} }{2}}{cos30} \\OB= \frac{\frac{27\sqrt{3} }{2}}{\frac{\sqrt{3} }{2} } \\OB =27 \ cm

Thus for

Perimeter of equilateral triangle ABC is 81/√3 centimeters,

The radius of equilateral triangle ABC is 27 cm

The apothem of equilateral triangle ABC is 13.5 cm

4 0
3 years ago
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