The function that has a vertex on the y-axis is f(x) = (x - 2)(x + 2)
<h3>How to determine the function?</h3>
For a function to have its vertex on the y-axis, then the coordinate of the vertex must be:
(h,k) = (0,y)
A quadratic function is represented as:
f(x) = (x - h)^2 + k
So, we have:
f(x) = (x - 0)^2 + k
Evaluate
f(x) = x^2 + k
From the list of options, we have:
f(x) = (x - 2)(x + 2)
Expand
f(x) = x^2 - 4
Hence, the function that has a vertex on the y-axis is f(x) = (x - 2)(x + 2)
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Answer:
assume the formula is true for n is equal to k prove that result is true for n is equal to k + 1 hence result proves since the thorum is true for n is equal to 1 and n k + 1 is unit through a and
Answer:
20×(5×(-16) = (20×5)×(-16)
Step-by-step explanation:
They both equal -1600
Answer:
mbkjbikjjbkbkjbjbjkbjkjbkbjkjbk
Step-by-step explanation:
Answer:
y = 314
Step-by-step explanation:
y = 650 - 16x
y = 650 - 16(21)
y = 650 - 336
y = 314
