May i please get help i beg you

An illusionist needs up to 10 volunteers for a show. the illusionist needs no fewer than 4 female volunteers. let x represent th

tatyana61 [14]

An illusionist needs up to 10 volunteers for a show. the illusionist needs no fewer than 4 female volunteers. let x represent the number of femalevolunteers and y represent the number of male volunteers.which inequalities model the situation?select each correct answer.

A- x + y < 10
B- x + y ≤ 10 & x ≥ 4
C- x > 4
D- x ≥ 4
E- y > 0
G- y ≥ 0

Solution :
option "B" is correct. Because the total number of male and female should be upto 10. and the number of female should be equal or greater than 4 but not less than it.

4 0

3 years ago

Read 2 more answers

Evaluate the expression when X= -2 x^2 + 9x + 3

TiliK225 [7]

Answer:

-11

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Step-by-step explanation:

Step 1: Define

x² + 9x + 3

x = -2

Step 2: Evaluate

Substitute in x: (-2)² + 9(-2) + 3
Exponents: 4 + 9(-2) + 3
Multiply: 4 - 18 + 3
Subtract: -14 + 3
Add: -11

3 0

3 years ago

USA Today reports that about 25% of all prison parolees become repeat offenders. Alice is a social worker whose job is to counse

pychu [463]

Answer:

a) $P(X=0)=(4C0)(0.75)^0 (1-0.75)^{4-0}=0.0039$

$P(X=1)=(4C1)(0.75)^1 (1-0.75)^{4-1}=0.0469$

$P(X=2)=(4C2)(0.75)^2 (1-0.75)^{4-2}=0.211$

$P(X=3)=(4C3)(0.75)^2 (1-0.75)^{4-3}=0.422$

$P(X=4)=(4C4)(0.75)^2 (1-0.75)^{4-4}=0.316$

b) $E(X) = np = 4*0.75=3$

c) $Sd(X) =\sqrt{np(1-p)}=\sqrt{4*0.75*(1-0.75)}=0.866$

d) $P(X \geq 3) \geq 0.98$

And the dsitribution that satisfy this is $X\sim Binom(n=9,p=0.75$

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Let X the random variable of interest, on this case we now that:

$X \sim Binom(n=4, p=1-0.25=0.75)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

Part a

$P(X=0)=(4C0)(0.75)^0 (1-0.75)^{4-0}=0.0039$

$P(X=1)=(4C1)(0.75)^1 (1-0.75)^{4-1}=0.0469$

$P(X=2)=(4C2)(0.75)^2 (1-0.75)^{4-2}=0.211$

$P(X=3)=(4C3)(0.75)^2 (1-0.75)^{4-3}=0.422$

$P(X=4)=(4C4)(0.75)^2 (1-0.75)^{4-4}=0.316$

Part b

The expected value is givn by:

$E(X) = np = 4*0.75=3$

Part c

For the standard deviation we have this:

$Sd(X) =\sqrt{np(1-p)}=\sqrt{4*0.75*(1-0.75)}=0.866$

Part d

For this case the sample size needs to be higher or equal to 9. Since we need a value such that:

$P(X \geq 3) \geq 0.98$

And the dsitribution that satisfy this is $X\sim Binom(n=9,p=0.75$

We can verify this using the following code:

"=1-BINOM.DIST(3,9,0.75,TRUE)" and we got 0.99 and the condition is satisfied.

4 0

3 years ago

Write a rule to describe the transformation.

Angelina_Jolie [31]

Step-by-step explanation:

The function translation / transformation rules: f (x) + b shifts the function b units upward. f (x) − b shifts the function b units downward. f (x + b) shifts the function b units to the left

4 0

3 years ago

Where can the perpendicular bisectors of an obtuse triangle intersect

Flura [38]

The answer for this question is incenter

3 0

3 years ago

May i please get help i beg you​

May i please get help i beg you