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3 years ago

Please help, I don't know how to get all the angle measurements.

Mathematics

1 answer:

SOVA2 [1]3 years ago

8 0

Answer:

Step-by-step explanation:

From the markings p and q are opposite equal sides. That means that p = q

Since = 24 then q must also be 24

r is an exterior angle. It is equal to the two remote interior angles which in this case are p and q

r = p + q But p and q are both equal

r = 24 + 24

r = 48

From the markings r and s are opposite equal sides. That means that r and s are equal.

s = r

s = 48

t is another exterior angle. It is = to the sum of the two interior angles

so t = r + S

t = 48 + 48

t = 96

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borishaifa [10]

Answer:

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Step-by-step explanation:

Given the data :

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Class interval ____, Frequency _ C/frequency

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3 years ago

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mr_godi [17]

Answer:

Step-by-step explanation:

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4 0

3 years ago

A circle has the equation 2x²+12x+2y²−16y−150=0.

KonstantinChe [14]

Answer: B. The coordinates of the center are (-3,4), and the length of the radius is 10 units.

Step-by-step explanation:

The equation of a circle in the center-radius form is:

$(x-h)^{2} +(y-k)^{2}=r^{2}$ (1)

Where $(h,k)$ are the coordinates of the center and $r$ is the radius.

Now, we are given the equation of this circle as follows:

$2x^{2}+12x+2y^{2}-16y-150=0$ (2)

And we have to write it in the format of equation (1). So, let's begin by applying common factor 2 in the left side of the equation:

$2(x^{2}+6x+y^{2}-8y-75)=0$ (3)

Rearranging the equation:

$x^{2}+6x+y^{2}-8y=75$ (4)

$(x^{2}+6x)+(y^{2}-8y)=75$ (5)

Now we have to complete the square in both parenthesis, in order to have a perfect square trinomial in the form of $(a\pm b)^{2}=a^{2}\pm+2ab+b^{2}$ :

For the first parenthesis:

$x^{2}+6x+b^{2}$

We can rewrite this as:

$x^{2}+2(3)x+b^{2}$

Hence in this case $b=3$ and $b^{2}=9$ :

$x^{2}+2(3)x+3^{2}=x^{2}+6x+9=(x+3)^{2}$

For the second parenthesis:

$y^{2}-8y+b^{2}$

We can rewrite this as:

$y^{2}-2(4)y+b^{2}$

Hence in this case $b=-3$ and $b^{2}=9$ :

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Rearranging:

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At this point we have the circle equation in the center radius form $(x-h)^{2} +(y-k)^{2}=r^{2}$

Hence:

$h=-3$

$k=4$

$r=\sqrt{100}=10$

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4 years ago

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Yuliya22 [10]

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Step-by-step explanation:

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2 years ago

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vlada-n [284]

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Step-by-step explanation:

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3 years ago

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