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Burka [1]
3 years ago
12

Find the sum and express it in simplest form (8a^2 + 6a + 5) + (-3a^2 - 2a)

Mathematics
2 answers:
PIT_PIT [208]3 years ago
5 0
What we are going to do with this problem is combine all the like terms. 
so to begin, we notice that there are two numbers with a^2 involved, and two numbers with an a.

thus:
8a^{2}+(-3a^{2} is going to equal 5a^{2} because adding a negative is just like subtracting.

then we move on to (6a)-(2a) giving us 4a
5 is the only term that stays the same because there are no other similar terms.
last but not least, put the equation together!

answer: 5a^{2}+4a+5
Contact [7]3 years ago
4 0
(8a^2 + 6a + 5) + (-3a^2 -2a)

5a^2 + 4a + 5 <------------ answer
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In the textile industry, a manufacturer is interested in the number of blemishes or flaws occurring every 100 feet of material.
Naily [24]

Answer:

b. Binomial distribution.

Step-by-step explanation:

As a manufacturer is interested in the number of blemishes or flaws occurring every 100 feet of material which shows that only two possible outcomes with fixed number of trials are present here, so the probability distribution that has the greatest chance of applying to this situation is a binomial distribution that summarizes the possibility that a value will take one of two independent values under a provided set of parameters.

5 0
3 years ago
Which of the following equations is equivalent to 4x -y=3`?
kupik [55]

Answer:

x-intercept = (3/4,0)

y'intercept = (0,-3)

Step-by-step explanation:

Not sure what conversion you need but here are the intercepts

7 0
3 years ago
No link or bot answer the question
Alex

Answer:

5

Step-by-step explanation:

76+2^2

76+4÷4^4

76+4÷16

80÷16

=5

3 0
3 years ago
Read 2 more answers
The base of an open rectangular box is of length (2x+5) cm and width x cm. The area of this base is 58cm^2. The height of the op
andreev551 [17]

<u>B) </u>x   =4.28

<u>C) </u> volume =  135.25cm^3 .

<u>Step-by-step explanation:</u>

Here we have , The base of an open rectangular box is of length (2x+5) cm and width x cm. The area of this base is 58cm^2. The height of the open box is (x-2) cm. We need to find the following :

a) show that 2x^2+5x-58=0

We know that area of rectangle = length(width)

⇒ Area = length(width)

Putting values according to question we get :

⇒ 58 = (2x+5)(x)

⇒ 58 = (2x^2+5x)

⇒  2x^2+5x - 58 = 0

b) solve the equation in the question above, giving your answer to 2 decimal places

Solving this equation :

⇒  2x^2+5x - 58 = 0

By quadratic formula

⇒ x   = \frac{-b \pm \sqrt{b^2-4ac} }{2a}

⇒ x   = \frac{-5 \pm \sqrt{5^2-4(2)(-58)} }{2(2)}

⇒ x   = \frac{-5 \pm 22.11}{4}

⇒ x   = \frac{-5 + 22.11}{4} , x   = \frac{-5 - 22.11}{4}    { Since side can't be negative ! }

⇒ x   =4.28

c) calculate the volume of the box, stating units of you answer

Since x = 4.28 , other sides are

2x+5=2(4.28)+5=13.56\\x-2=4.28-2=2.28

We know that volume is given by :

⇒ length(width)(height)

⇒ 13.86(4.28)(2.28)

⇒ 135.25cm^3

Therefore , volume =  135.25cm^3 .

7 0
3 years ago
The standard deviation of quiz scores is 5.6. Describe the quiz scores
Lyrx [107]

We have been given a table of quiz scores whose standard deviation is 5.6. We are asked to find the test scores that are within one standard deviation of the mean.

First of all, we will find the mean of the test scores using average formula.

\text{Average}=\frac{\text{Sum of data points}}{\text{Number of data points}}

\text{Average}=\frac{25+13+16+30+27+22+19+22+15+28+27+29}{12}

\text{Average}=\frac{273}{12}

\text{Average}=22.75

The scores within one standard deviation would be mean plus one SD and mean minus one SD that is:

22.75-5.6\text{ and } 22.75+5.6

17.15\text{ and } 28.35

Therefore, the quiz scores 17.15 and 28.35 are within one standard deviation of the mean.

7 0
4 years ago
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