Answer:
Tthe distance between
and
will be:
Step-by-step explanation:
Given the points





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Therefore, the distance between
and
will be:
Reflected would make a mirror image.
X is located at (1 ,-3)
Since it is being reflected across the Y axis, the X value would be the same.
The Y value is 4 units below Y=1 ( the mirror line) so the new Y value would be 4 units above the mirror line ( 4+1 = 5)
This means X' would be at (1.5)
Answer:
y + 10 = -1/3 (x - 6) OR y = -1/3x-8
Step-by-step explanation:
take the slope of y = -1/3x - 2 (the slope is -1/3)
plug the slope and the point into this equation: y - y1 = m (x - x1)
m represents your slope, y1 and x1 represnt your points so just plug in
so y + 10 = -1/3 (x - 6) or y = -1/3x-8 (subtract 10 from both sides and distribute the -1/3 to (x -6)).
9514 1404 393
Answer:
(b) 458 ft²
Step-by-step explanation:
The total area is the sum of the L-shaped front and back areas and the areas of the 6 rectangular faces.
The front L-shaped area can be considered to be a 12 ft × 12 ft square with a 5 ft × 7 ft rectangle cut from the upper left corner. Its area is then ...
(12 ft)(12 ft) -(5 ft)(7 ft) = (144 -35) ft² = 109 ft² . . . . front area
__
The sum of the areas of the rectangular faces is the product of the width of the figure (5 ft) and the perimeter of the L-shaped face. That perimeter is the sum of the edge lengths. Starting from the lower-left corner and working clockwise, we find the perimeter to be ...
7 ft + 7 ft + 5 ft + 5 ft + 12 ft + 12 ft = 48 ft
Then the sum of rectangular face areas is ...
(48 ft)(5 ft) = 240 ft² . . . . rectangular face area
The total surface area is then ...
2×front area + rectangular face area
= 2×109 ft² +240 ft² = 458 ft² . . . . total surface area
I think the answer is B not sure tho