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2 years ago

Will I see an uplift in SEO traffic from a domain migration?

1 answer:

6 0

It should be noted that a domain migration will temporarily lead to a loss of traffic but in the long run, the person will see an uplift in SEO traffic.

A domain migration simply means the shifting between domains without impairment.

A domain migration will result in a temporary loss of traffic. This is because it needs time for it to be processed and updated. After this is done, there will be an uplift in SEO traffic.

Learn more about migration on:

brainly.com/question/1086680

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We can describe 3x-2 as an expression how can we describe the parts of the expression that the arrows point to?

Oksanka [162]

Answer:

If the arrow is pointing to the -2, that’s the constant.

If the arrow is pointing at x, that’s the variable.

If the arrow is pointing at 3, that’s the coefficient.

8 0

3 years ago

860 meters of wire are used to build a wire fence around a square lot. How long is one side of the lot

kirill115 [55]

One side of the lot is 215

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3 years ago

A field is shaped like the figure shown what is the area of the field? use 3.14 for pie

jok3333 [9.3K]

Answer:

need more information

Step-by-step explanation:

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3 years ago

Workers at a certain soda drink factory collected data on the volumes (in ounces) of a simple random sample of 17 cans of the so

LiRa [457]

Answer:

a)Null Hypothesis: $\sigma^2 \geq 0.0196$

Alternative hypothesis: $\sigma^2$

b) $\chi^2 =\frac{17-1}{0.0196} 0.0121 =9.878$

c) $p_v =P(\chi^2$

d) If we compare the p value we see that is higher than the significance level so then we have enough evidence to FAIL to reject the null hypothesis and we can't say that the true deviation is significantly lower than 0.14

Step-by-step explanation:

Data given

$n=17$ represent the sample size

$\alpha=0.01$ represent the confidence level

$s^2 =0.11^2 = 0.0121$ represent the sample variance obtained

$\sigma^2_0 =0.14^2 = 0.0196$ represent the value that we want to test

Part a System of hypothesis

On this case we want to check if the population deviation is lower than 0.14, so the system of hypothesis would be:

Null Hypothesis: $\sigma^2 \geq 0.0196$

Alternative hypothesis: $\sigma^2$

Part b: Calculate the statistic

The statistic is given by:

$\chi^2 =\frac{n-1}{\sigma^2_0} s^2$

And replacing we got:

$\chi^2 =\frac{17-1}{0.0196} 0.0121 =9.878$

Part c: Calculate the p value

In order to calculate the p value we need to find first the degrees of freedom , on this case 17-1=16. And since is a left tailed test the p value would be given by:

$p_v =P(\chi^2$

In order to find the p value we can use the following code in excel:

"=CHISQ.DIST(9.878,16,TRUE)"

Part d: Conclusion

If we compare the p value we see that is higher than the significance level so then we have enough evidence to FAIL to reject the null hypothesis and we can't say that the true deviation is significantly lower than 0.14

8 0

3 years ago

Please help will give branniest

egoroff_w [7]

The answer is A

To explain more on why it’s A

Because, Y, which is the shaded part on the graph

Is less than negative 2x, as you can see is above y

6 0

4 years ago