Answer:
The first equation, f(x)=100(3/5)^(x), represent the graph
Answer:
-5, -2, -1, 0, 7
the answer is D
Step-by-step explanation:
The formula that is useful for solving both of these problems is ...

9. Given v₁=15, a=9.8, d=10, find v₂.
... (v₂)² = 15² + 2·9.8·10
... v₂ = √421 ≈ 20.5 . . . . m/s
10. Given d=12 m when a=-9.8 m/s² and v₂=0, find d when a=0.17·(-9.8 m/s²).
The formula tells us that d=(v₁)²/(2a), which is to say that the distance is inversely proportional to the acceleration. If acceleration is 0.17 times that on earth, distance will be 1/0.17 ≈ 5.88 times that on earth.
(12 m)/0.17 ≈ 70.6 m
This is your answer:
<span>Trapezoid
JKLM is congruent to trapezoid J′K′L′M′ because you can map trapezoid
JKLM to trapezoid J′K′L′M′ by reflecting it across the line y = x and
then translating it 1 unit up, which is a sequence of rigid motions.</span>