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2 years ago

Please help due tmrw

Mathematics

2 answers:

shusha [124]2 years ago

5 0

Answer:

Step-by-step explanation:

less than equal to circle is filled

SashulF [63]2 years ago

5 0

Answer:

the answer that you are looking for would be A.

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Ross drives 340 miles in 5 hour if ross continues to drive at the same rate how many miles can he drive in 10 hours?

yKpoI14uk [10]

He can drive about 680 miles in 10 hours.

7 0

2 years ago

Mo spends £15 on ingredients to make 40 cookies.

ahrayia [7]

Given :

Mo spends £15 on ingredients to make 40 cookies.

He sells all 40 cookies for 50p each.

To Find :

The Mo's percentage profit.

Solution :

We know, 1 £ = 66.09 p.

So, total income is :

T = 40 × 50 p

T = 2000 p

T = £2000/66.09

T = £30.26

So, total profit is, P = £( 30.26 - 15 ) = £15.26 .

Hence, this is the required solution.

8 0

3 years ago

X2 is the GCF of this polynomial.

nadezda [96]

Answer:

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Y=arccos(1/x)<br><br> Please help me do them all! I don’t know derivatives :(

Stells [14]

Answer:

$f(x) = {sec}^{ - 1} x \\ let \: y = {sec}^{ - 1} x \rightarrow \: x = sec \: y\\ \frac{dx}{dx} = \frac{d(sec \: y)}{dx} \\ 1 = \frac{d(sec \: y)}{dx} \times \frac{dy}{dy} \\ 1 = \frac{d(sec \: y)}{dy} \times \frac{dy}{dx} \\1 = tan \: y.sec \: y. \frac{dy}{dx} \\ \frac{dy}{dx} = \frac{1}{tan \: y.sec \: y} \\ \frac{dy}{dx} = \frac{1}{ \sqrt{( {sec}^{2} \: y - 1}) .sec \: y} \\ \frac{dy}{dx} = \frac{1}{ |x | \sqrt{ {x }^{2} - 1} } \\ \therefore \frac{d( {sec}^{ - 1}x) }{dx} = \frac{1}{ |x | \sqrt{ {x }^{2} - 1} } \\ \frac{d( {sec}^{ - 1}5x) }{dx} = \frac{1}{ |5x | \sqrt{25 {x }^{2} - 1} }\\\\y=arccos(\frac{1}{x})\Rightarrow cosy=\frac{1}{x}\\x=secy\Rightarrow y=arcsecx\\\therefore \frac{d( {sec}^{ - 1}x) }{dx} = \frac{1}{ |x | \sqrt{ {x }^{2} - 1} }$

4 0

2 years ago

4x + 5y = 3<br>kx + 15y = 9 find k<br>

9966 [12]

Answer:

Step-by-step explanation:

4x + 5y = 3 ................ (i)

kx + 15y = 9................(ii)

Dividing eqn (ii) by 3, we get,

k/3 x + 5y = 3.............(iii)

Subtracting eqn (iii) by eqn (i), we get,

-4x - k/3 x = 0

or, -(4 - k/3 )x = 0

or, 4 - k/3 = 0/x

or, 4 - k/3 = 0

or, 4 = k/3

or, k = 4*3

:. k = 12 (Ans)

6 0

2 years ago