If triangle KMN is congruent with triangle LMN, then:
1) KM must be congruent with LM→KM=LM→
x+2y=3x-y→x+2y-x-2y=3x-y-x-2y→0=2x-3y→2x-3y=0 (1)
2) KN must be congruent with LN→KN=LN→
5x+3y=8x-7→5x+3y-5x-3y+7=8x-7-5x-3y+7→7=3x-3y→3x-3y=7 (1)
We have a system of two equations and two unkowns:
(1) 2x-3y=0
(2) 3x-3y=7
Subtracting equation (1) from equation (2)
(3x-3y)-(2x-3y)=7-0
3x-3y-2x+3y=7
x=7
Replacing x=7 in equation (1)
(1) 2x-3y=0→2(7)-3y=0→14-3y=0→
14-3y+3y=0+3y→14=3y→14/3=3y/3→14/3=y→y=14/3
The length of the hypotenuse is:
KN=5x+3y=5(7)+3(14/3)=35+14→KN=49
or
LN=8x-7=8(7)-7=56-7→LN=49
Answer: Option C. 49
The answer is 2.6 m/s
The speed (v) is distance (d) through time (t).
v = d/t
We know:
d = 390 m
t = 150 s
v = d/t
v = 390 m / 150s
v = = 2.6 m/s
The answer should be 12x cm power of 2
Answer:
the teachers would have 24 students per teacher. 10 students per tutor. There would need to be 11 tutors
Step-by-step explanation:
each tutor would have 10 students then if you do 11 times 10 you get 11
(hope this helps can I pls have brainlist (crown)☺️)
20-13=7+11=18 is the answer
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