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Hatshy [7]
3 years ago
11

An equation is written to represent the relationship between the temperature in Alaska during a snow storm, y, as it relates to

the time in hours, x, since the storm started. A graph of the equation is created. Which quadrants of a coordinate grid should be used to display this data? Quadrant 1 only Quadrant 1 and 2 only Quadrant 4 only Quadrant 1 and 4 only
Mathematics
1 answer:
Serhud [2]3 years ago
8 0

Answer:

either of ...

• quadrant 1 only

• quadrant 1 and 4 only

Step-by-step explanation:

Time since the storm started is always positive. The values of x are positive in quadrants 1 and 4.

Temperatures in a blizzard are not always terribly cold. Some of the coldest snowstorms on record have temperatures in the range of +5 °F to +18 °F. These values are negative temperatures on the Celsius scale, so the quadrant used for plotting them will depend on the temperature scale you choose.

While temperatures in Alaska can be well below zero (on either the F or C temperature scales), the air usually has to warm up to the range indicated above before it can snow. US temperatures are generally reported using the Fahrenheit scale, but weather records are often kept using the Celsius scale.

I would be inclined to choose "Quadrant 1 and 4 only", but arguments can be made for "1 only" and "4 only" as suggested above.

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Write an equation that goes through (8,1) and is perpendicular to 2y + 4x =12
Serggg [28]

Answer:

2y -x + 6 = 0

Step-by-step explanation:

Here a equation and a point is given to us and we are interested in finding a equation which is perpendicular to the given equation and passes through the given point .

The given equation is ,

\sf \longrightarrow 2y + 4x = 12 \\

\sf \longrightarrow 4x + 2y = 12

Firstly convert this into slope intercept form , to find out the slope of the line.

\sf \longrightarrow 2y = -4x +12\\

\sf \longrightarrow y =\dfrac{-4x+12}{2}\\

\sf \longrightarrow y =\dfrac{-4x}{2}+\dfrac{12}{2}\\

\sf \longrightarrow \red{ y = -2x + 6 }

Now on comparing it to slope intercept form which is y = mx + c , we have ,

  • m = -2

And as we know that the product of slopes of two perpendicular lines is -1 . So the slope of the perpendicular line will be negative reciprocal of the slope of the given line. Therefore ,

\sf \longrightarrow m_{\perp}=\dfrac{-1}{-2}=\red{\dfrac{1}{2}}

Now we may use the point slope form of the line to find out the equation of the line using the given point . The point slope form is,

\sf \longrightarrow y - y_1 = m(x - x_1)

Now on substituting the respective values we have,

\sf \longrightarrow y - 1 = \dfrac{1}{2}(x-8)\\

\sf \longrightarrow 2(y-1 )= x -8 \\

\sf \longrightarrow 2y -2=x-8\\

\sf \longrightarrow \underline{\boxed{\bf 2y - x + 6=0}}

5 0
3 years ago
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