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3 years ago

The product of twice a number and six is the same as the difference of eleven times the number and 6/5 . Find the number

Mathematics

1 answer:

Rom4ik [11]3 years ago

3 0

Answer:

-6/5

Step-by-step explanation:

solution;

let,the number be x,

product of <u>twice</u><u> </u><u>of</u><u> </u><u>x</u> and <u>six</u> = the <u>difference </u>

<u>difference of eleven times x and 6/5</u>

or, (2x×6)=(11×x)-(6/5)

or, 12x = 11x - 6/5

or, 12x - 11x = -6/5

therefore,x =-6/5

Therefore, the number required is (-6/5) whose product of twice a number and six is the same as the difference of eleven times the number and 6/5 .

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attashe74 [19]

7/8
3/4
I'm order for them to have the same denominator you need to multiply so:
¾×2=6/8
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2 years ago

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The midpoint of AB is at (3,7) and A is at (0,-5). Where is B located?

olga nikolaevna [1]

$\bf \textit{middle point of 2 points }\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
&({{ \square }}\quad ,&{{ \square }})\quad 
% (c,d)
&({{ \square }}\quad ,&{{ \square }})
\end{array}\qquad
% coordinates of midpoint 
\left(\cfrac{{{ x_2}} + {{ x_1}}}{2}\quad ,\quad \cfrac{{{ y_2}} + {{ y_1}}}{2} \right)\qquad thus
\\
----------------------------\\$ $\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
A&({{ 0}}\quad ,&{{ -5}})\quad 
% (c,d)
B&({{ \square }}\quad ,&{{ \square }})
\end{array}\qquad
% coordinates of midpoint 
(3,7)\impliedby midpoint\qquad thus
\\ \quad \\
\left(\cfrac{{{ x_2 }} + {{ 0}}}{2}=3\quad ,\quad \cfrac{{{ y_2 }} + {{( -5)}}}{2}=7 \right)\to 
\begin{cases}
\cfrac{{{ x_2 }} + {{ 0}}}{2}=3
\\ \quad \\
\cfrac{{{ y_2 }} + {{ -5}}}{2}=7
\end{cases}
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solve\ for\ x_2\ and\ y_2$

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2 years ago

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Lostsunrise [7]

Answer:

d=−6c+24g

Step-by-step explanation:

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2 years ago

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The first three terms of an arithmetic sequence are as follows.

Katen [24]

Answer:

16,20

Step-by-step explanation:

As shown, you add four by each.

4+4=8

8+4=12

So, 12+4=16

16+4=20

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2 years ago

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What is the length of AB when A is (-7,-6) and B is (1,0)

NemiM [27]

Answer:

The answer is

<h2>10 units</h2>

Step-by-step explanation:

The distance between two points can be found by using the formula

$d = \sqrt{( {x1 - x2})^{2} + ({y1 - y2})^{2} } \\$

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

A (-7,-6) and B (1,0)

The distance between them is

$|AB| = \sqrt{( { - 7 - 1})^{2} + ({ - 6 - 0})^{2} } \\ = \sqrt{ ({ - 8})^{2} + ({ - 6})^{2} } \\ = \sqrt{64 + 36} \\ = \sqrt{100} \: \: \: \: \: \: \: \:$

We have the final answer as

<h3>10 units</h3>

Hope this helps you

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