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2 years ago

Angular when to use reactiveformsmodule.

Computers and Technology

1 answer:

WITCHER [35]2 years ago

3 0

Answer:

Image result for Angular when to use reactiveformsmodule.

In summaries, if forms are very important for your app, or reactive pattern are used in your app, you should use reactive forms. Otherwise your app have basic and simple requirement for forms such as sign in, you should use template-driven forms

Explanation:

Each form has a state that can be updated by many different interactions and its up to the application developer to manage that state and prevent it from getting corrupted. This can get hard to do for very large forms and can introduce a category of potential bugs

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1. How many bits would you need to address a 2M × 32 memory if:

Dominik [7]

Answer:

a) 23 b) 21
a) 43 b) 42
a) 0 b) 0

Explanation:

1) How many bits is needed to address a 2M * 32 memory

2M = 2^1*2^20, while item =32 bit long word

hence ; L = 2^21 ; w = 32

a) when the memory is byte addressable

w = 8; L = ( 2M * 32 ) / 8 = 2M * 4

hence number of bits = log2(2M * 4)= log2 ( 2 * 2^20 * 2^2 ) = 23 bits

b) when the memory is word addressable

W = 32 ; L = ( 2M * 32 )/ 32 = 2M

hence the number of bits = log2 ( 2M ) = Log2 (2 * 2^20 ) = 21 bits

2) How many bits are required to address a 4M × 16 main memory

4M = 4^1*4^20 while item = 16 bit long word

hence L ( length ) = 4^21 ; w = 16

a) when the memory is byte addressable

w = 8 ; L = ( 4M * 16 ) / 8 = 4M * 2

hence number of bits = log 2 ( 4M * 2 ) = log 2 ( 4^1*4^20*2^1 ) ≈ 43 bits

b) when the memory is word addressable

w = 16 ; L = ( 4M * 16 ) / 16 = 4M

hence number of bits = log 2 ( 4M ) = log2 ( 4^1*4^20 ) ≈ 42 bits

3) How many bits are required to address a 1M * 8 main memory

1M = 1^1 * 1^20 , item = 8

L = 1^21 ; w = 8

a) when the memory is byte addressable

w = 8 ; L = ( 1 M * 8 ) / 8 = 1M

hence number of bits = log 2 ( 1M ) = log2 ( 1^1 * 1^20 ) = 0 bit

b) when memory is word addressable

w = 8 ; L = ( 1 M * 8 ) / 8 = 1M

number of bits = 0

5 0

3 years ago

Assume that a gallon of paint covers about 350 square feet of wall space. Create anapplication with a main() method that prompts

Elena-2011 [213]

Answer:

import java.util.Scanner;

public class PaintClculator {

public static void main(String[] args) {

Scanner in = new Scanner(System.in);

System.out.println("Enter Values for length, width, and height of the room");

double length = in.nextDouble();

double width = in.nextDouble();

double height = in.nextDouble();

double wallArea = calculateWallArea(length,width,height);

double noGallons = calculatePaint(wallArea);

double price = price(noGallons);

System.out.println("Price is: "+ price);

}

// Creating Method to Calculate Wall Area

public static double calculateWallArea( double length, double width, double height){

// formular for the surface area of a room Area=2*length*heigth+2*width*height+lenth*width

double Area = 2*length*height+2*width*height+length*width;

System.out.println("Wall Area: "+Area);

return Area;

}

//Creating method to calculate amount of paint

public static double calculatePaint(double Area){

double noGallons = Area/350;

System.out.println("Number of gallons: "+noGallons);

return noGallons;

}

// Creating Method Calculate Price

public static double price(double noGallons){

return noGallons*32;

}

Explanation

Created Three Methods in all; calculateWallArea(), calculatePaint(), and price()
Method calculateWallArea() calculates area based on this formula Area=2*length*heigth+2*width*height+lenth*width
The value of Area is passed to method calculatePaint() Which calculates the number of gallons required to cover the area given that one gallon covers 350 wall space
Method price() calculates and dis[plays the price by calling method calculatePaint() that returns number of gallons. since one gallon is 32$

3 0

3 years ago

A _____ miniature battery operated transmitter that can be propelled through a non-metallic pipe or purpose of locating

Anna11 [10]

I think it is the model ET-2. Not quite sure.

7 0

3 years ago

Jack, a skillful hacker targeted a major banking services firm located in Japan, using the LOIC (Low Orbit Ion Cannon) tool, Jac

Elenna [48]

Answer:

denial-of-service attack (DoS attack) and distributed denial-of-service attack (DDoS attack)

Explanation:

Denial-of-service attack -

It is a type of cyber attack , where the hacker can create a machine or any network resource , which is capable to disrupt the server of the host , with the help of the internet , is referred to as the denial of service attack .

The task is accomplished with by flooding the host with many superfluous requests , which can overload the system .

In case of the distributed denial-of-service attack , the flooding is done by many different sources .

Hence , from the given scenario of the question ,

The correct answer is denial-of-service attack (DoS attack) and distributed denial-of-service attack (DDoS attack) .

4 0

3 years ago

Importance/Role of the information systems in Education

JulsSmile [24]

Answer:

Information technology can be used to promote opportunities for knowledge dissemination.

Explanation:

It can help the teachers and students have up-to-date information and knowledge. The accurate and right information is necessary for effective teaching and learning; and information technology

7 0

2 years ago