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anzhelika [568]
2 years ago
14

HELP PLS which box has the largest IQR

Mathematics
1 answer:
klio [65]2 years ago
6 0

Answer:

Box B i think.

Step-by-step explanation:

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The square root of -100 = ___ + ___i
ddd [48]

Answer:

The square root of -100 is 10i

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
What is 70/10 equivalent fraction?
kaheart [24]
The answer is 7 because 70 ÷ 10 = 7.
6 0
3 years ago
What is the perimeter of the figure in the diagram (round to three decimal places if necessary)? A) 54.5 B) 42.634 C) 39.5 D) 27
beks73 [17]

Answer:

D

Step-by-step explanation:

First add all the simple line up so;

8 + 7 + 3 + 2 = 20

Then use Pythagoras to work out the lengths of the remaining lines

\sqrt{ {2}^{2}  +  {4}^{2} }   = 2 \sqrt{5}  \\  \sqrt{ {3}^{2}  +  {1}^{2} }  =  \sqrt{10}  \\ 20 +  \sqrt{10}  + 2 \sqrt{5} = 27.63441362

So to three decimal places it would be;

27.634

7 0
3 years ago
A company produces and sells widgets and gizmos. In January the company sold 350 items for a total of $9,000. If each widget sol
iren [92.7K]

Answer:

The company sold 100 widgets and 250 gizmos.

Step-by-step explanation:

Let x_1 be the number of widgets sold and x_2 be the number of gizmos sold.

We are told that the company sold 350 items. We can represent this information in an equation as:

x_1+x_2=350...(1)

We have been given that a each widget sold for $35 and each gizmo sold for $22. The company sold 350 items for a total of $9,000.

We can represent this information in an equation as:

35x_1+22x_2=9,000...(2)

From equation (1), we will get:

x_2=350-x_1

Substitute this value in equation (2):

35x_1+22(350-x_1)=9,000

35x_1+7,700-22x_1=9,000

13x_1+7,700=9,000

13x_1+7,700-7,700=9,000-7,700

13x_1=1,300

\frac{13x_1}{13}=\frac{1,300}{13}

x_1=100

Therefore, the company sold 100 widgets.

Substitute x_1=100 in equation (1):

100+x_2=350

100-100+x_2=350-100

x_2=250

Therefore, the company sold 250 gizmos.

3 0
3 years ago
Read 2 more answers
A slug travels 3 centimeters in 3 seconds. A snail travels 6 centimeters in 6 seconds Both travel at constant speeds. Mai says,
Mashutka [201]

Answer:

No I dont agree with Mai. As both the slug and snail are moving with constant speed.

Step-by-step explanation:

Given that:

A slug travels 3 centimeters in 3 seconds.

Speed of slug = distance/ time = 3/3 = 1 cms^-1

A slug travels 3 centimeters in 3 seconds.

Speed of snail = distance/ time = 6/6 = 1 cms^-1

Hence both have constant speeds only the time span for snail is increased which gives more distance it doesn't means that it had covered more distance.

i hope it will help you!

4 0
3 years ago
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