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GenaCL600 [577]
2 years ago
14

Examine these points on line u and line v. Line u: (9, –8), (5, 4) Line v: (4, 2), (7, –7) How many points of intersection are t

here between line u and line v? zero one two infinitely many.
Mathematics
1 answer:
Nezavi [6.7K]2 years ago
3 0

There is no point of intersection between line u and line v.

Given that

These points on line u and line v.

Line u: (9, –8), (5, 4)

Line v: (4, 2), (7, –7)

We have to determine

How many points of intersection are there between line u and line v?

According to the question

To determine the point of intersection follows all the steps given below.

Line u: (9, –8), (5, 4)

The slope of the line u is,

\rm Slope = \dfrac{4-(-8)}{5-9}\\\\Slope = \dfrac{4+8}{-4}\\\\Slope = \dfrac{12}{-3}\\\\Slope = -4

And the value of c is at point (5, 4) is,

\rm y = mx+c\\\\4= -3\times 5+c\\\\c = 4+15\\\\c=19

The equation of u is y = -3x + 19.

And

Line v: (4, 2), (7, -7)

The slope of line V is,

\rm Slope = \dfrac{-7-(2)}{7-4}\\\\Slope = \dfrac{-7-2}{3}\\\\Slope = \dfrac{-9}{3}\\\\Slope = -3

And the value of c is at point (4, 2) is,

\rm y = mx+c\\\\2= -3\times 4+c\\\\c = 2+12\\\\c=14

The equation of u is y = -3x + 14.

The slopes of them are equal and their y-intercepted are not equal.

Line u is parallel to line v.

Hence, there is no point of intersection between line u and line v.

To know more about Slope click the link given below.

brainly.com/question/2514839

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Which equation shows how (-10,8) can be used to write the equation of this line in point-slope from?
NeTakaya

Options :

y – 8 = –0.15(x – 10)

y + 8 = –0.15(x – 10)

y – 8 = –0.2(x + 10)

y + 8 = –0.2(x – 10)

Answer:

y – 8 = –0.2(x + 10)

Step-by-step explanation:

(-10, 8)

General equation in point - slope form:

y - y1 = m(x - x1)

m = slope

Given the points : ( - 10, 8)

x1= - 10 ; y1 = 8

y - y1 = m(x - x1)

Substitute the values of x and y into the equation :

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