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3 years ago

12. Your project specifications call for a business rule that the database design can't

Computers and Technology

1 answer:

fomenos3 years ago

8 0

A lot of business rules needs to be triggered so as to run.

In making of business rule, one can select triggers to run some specific events or run using some particular specified frequency.

The trigger options differs based on the type of rule you are interested in. One can also use multiple triggers when using a single rule.

Learn more about rules from.

brainly.com/question/5707732

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A set of blocks contains blocks of heights 1,2, and 4 centimeters. Imagine constructing towers of piling blocks of different hei

SashulF [63]

Answer:

In studies about new medicines, researchers usually give one group of patients the medicine that is designed to treat an illness. They give another group of patients a placebo, which is taken the same way as the medicine but does not actually contain the ingredients of any medicine. Different medicines are tested in different experiments, but the placebos usually contain the same non-medical ingredients. If both groups of patients are healed, then researchers cannot be sure whether the medicine caused improvement, but if the group given the medicine is healed while the group given the placebo remains ill, researchers can conclude that the medicine causes the illness to go away.

In medical experiments, which group receives placebos?

the experimental group

the control group

both the experimental and control groups

neither the experimental nor control group

Explanation:

5 0

3 years ago

A datagram network allows routers to drop packets whenever they need to. The probability of a router discarding a packetis p. Co

tresset_1 [31]

Answer:

a.) k² - 3k + 3

b.) 1/(1 - k)²

c.) $k^{2} - 3k + 3 * \frac{1}{(1 - k)^{2} }\\\\= \frac{k^{2} - 3k + 3 }{(1-k)^{2} }$

Explanation:

a.) A packet can make 1,2 or 3 hops

probability of 1 hop = k ...(1)

probability of 2 hops = k(1-k) ...(2)

probability of 3 hops = (1-k)²...(3)

Average number of probabilities = (1 x prob. of 1 hop) + (2 x prob. of 2 hops) + (3 x prob. of 3 hops)

= (1 × k) + (2 × k × (1 - k)) + (3 × (1-k)²)

= k + 2k - 2k² + 3(1 + k² - 2k)

∴mean number of hops = k² - 3k + 3

b.) from (a) above, the mean number of hops when transmitting a packet is k² - 3k + 3

if k = 0 then number of hops is 3

if k = 1 then number of hops is (1 - 3 + 3) = 1

multiple transmissions can be needed if K is between 0 and 1

The probability of successful transmissions through the entire path is (1 - k)²

for one transmission, the probility of success is (1 - k)²

for two transmissions, the probility of success is 2(1 - k)²(1 - (1-k)²)

for three transmissions, the probility of success is 3(1 - k)²(1 - (1-k)²)² and so on

∴ for transmitting a single packet, it makes:

∞ n-1

T = ∑ n(1 - k)²(1 - (1 - k)²)

n-1

= 1/(1 - k)²

c.) Mean number of required packet = ( mean number of hops when transmitting a packet × mean number of transmissions by a packet)

from (a) above, mean number of hops when transmitting a packet = k² - 3k + 3

from (b) above, mean number of transmissions by a packet = 1/(1 - k)²

substituting: mean number of required packet = $k^{2} - 3k + 3 * \frac{1}{(1 - k)^{2} }\\\\= \frac{k^{2} - 3k + 3 }{(1-k)^{2} }$

6 0

3 years ago

A computer can manipulate symbols as if it understands the symbols and is reasoning with them, but in fact it is just following

Law Incorporation [45]

Answer:

The symbols may or may not have meaning, but the machine does not need to know how the symbols are interpreted in order to manipulate the symbols in the right way.

Explanation:

The computer can change the symbols in the case when the computer understand but in actual following the cut-paste rules without having any understanding this is because the symbols might be have meaning or not but if we talk about the machine so actually they dont know how the symbols are interpreted and how it can be used so that it can be change in the accurate way