It's been a while since I have worked out problems like this. You may need to check.
hope this helps :)
A. 4 . . . Yes. 52/4 = 13
b. 26 . . . Yes. 52/26 = 2
<em>c. 3 . . . . No. 52/3 = 17 and 1/3</em>
d). 13 . . Yes. 52/13 = 4
Where x is 4 the corresponding y is 5. Your answer is 5.
Answer:
1430
Step-by-step explanation:
Given that a standard deck of cards is 52 cards, we have 13 Diamonds and we need 4 diamonds.
Hence, we have 13C4.
Also, we have 4 kings in a standard deck of cards, and in which we have 2 black kings but we need 1 king.
Hence we have a 2C1
Therefore:
13C4 * 2C1
=> 13! ÷ [4! (13 - 4)!] * 2! ÷ [1! (2-1)!]
=> 13! ÷ [4! (9)!]
=> (1 x 2 x 3 x 4 x 5 x 6 x 7 x 8 x 9 x 10 x 11 x 12 x 13) ÷ [(1 x 2 x 3 x 4) (1 x 2 x 3 x 4 x 5 x 6 x 7 x 8 x 9)]
=> (10 x 11 x 12 x 13) ÷ 24
=> (17160 ÷ 24) * (24 ÷ 6)
=> 715
2! ÷ [1! (2-1)!]
=> 2
Hence, we have 715 * 2
=> 1430
Hence, in this case, the correct answer to the question is 1430
Answer:
B.
Step-by-step explanation:
Trust me.
I just did it.
