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noname [10]
3 years ago
6

A horizontal board of negligible thickness and area 1. 0 m2 hangs from a spring scale that reads 70 n when a 4. 0 m/s wind moves

above the board. The air below the board is stationary. When the wind stops, the scale reads answer n. The density of air is 1. 25 kg/m3 and treat the air as an ideal fluid.
SAT
1 answer:
andrey2020 [161]3 years ago
3 0

Answer:

A horizontal board of negligible thickness and area 2.0 m2 hangs from a spring scale that reads 80 N when a 4.0 m/s wind moves beneath the board

Explanation:

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Describe the steps used to graph the equation 4x-2y=8 with an x- and y- intercepts.
hram777 [196]

Answer:

x=1/2y+2

y=2x-4

Explanation:

For x-intercept:

4x-2y=8

-> subtract -2y on both sides

4x=2y+8

-> divide 4 on both sides to isolate the x

x=1/2y+2

For y-intercept:

4x-2y=8

-> subtract 4x on both sides

-2y=-4x+8

-> divide -2 on both sides to isolate the y

y=2x-4

8 0
3 years ago
Consider the following line integral. C xy dx + x2y3 dy, c is counterclockwise around the triangle with vertices (0, 0), (1, 0),
Sedaia [141]

It looks like the integral is

\displaystyle \int_C xy \, dx + x^2y^3 \, dy

Let's close the loop by adding a line integral over the line segment joining (1, 4) to (0, 0). Then the closed loop is the triangular region

T = {(x, y) : 0 ≤ x ≤ 1 and 0 ≤ y ≤ 4x}

Since the integrand has no singularities over or on the boundary of T, we have by Green's theorem

\displaystyle \int_C xy \, dx + x^2y^3 \, dy = \iint_T \left(\frac{\partial(x^2y^3)}{\partial x} - \frac{\partial(xy)}{\partial y}\right) \, dx \, dy = \int_0^1 \int_0^{4x} (2xy^3 - x) \, dy \, dx

Compute the double integral:

\displaystyle \int_0^1 \int_0^{4x} (2xy^3 - x) \, dy \, dx = \int_0^1 \int_0^{4x} \left(128x^5 - 4x^2\right) \, dx = \frac{60}3

From this result, we subtract the line integral over the extra line segment we added. Parameterize this path by

C' : {(1 - t, 4 - 4t) : 0 ≤ t ≤ 1}

The line integral over C' is

\displaystyle \int_{C'} xy \, dx + x^2y^3 \, dy = \int_0^1 (1-t)(4-4t)(-dt) + (1-t)^2(4-4t)^3(-4\,dt)

\displaystyle \int_{C'} xy \, dx + x^2y^3 \, dy = \int_0^1 \left(256 t^5-1280 t^4+2560 t^3-2564 t^2+1288 t-260 \right) \, dt = -44

so that the line integral over C alone is 60/3 - (-44) = 64.

3 0
3 years ago
Which of the following elements do you expect to be most like sulfur?.
Vikki [24]

The elements that are expected to have similar characteristics with sulfur are oxygen, selenium, tellurium and polonium.

<h3>Elements in the same group</h3>

Elements in the same group in the periodic table share similar chemical characteristics.

<h3>Elements in the same group as sulfur</h3>

The elements found in the same group as sulfur, that share similar chemical characteristics include;

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Thus, the elements that are expected to have similar characteristics with sulfur are oxygen, selenium, tellurium and polonium.

Learn more about elements in the same group here: brainly.com/question/4098881

3 0
2 years ago
Define the atmosphere and explain the importance thereof.
nata0808 [166]

Answer:

The atmosphere is a thin layer of gases that surrounds the Earth. It seals the planet and protects us from the vacuum of space. It protects us from electromagnetic radiation given off by the Sun and small objects flying through space such as meteoroids.

4 0
3 years ago
The function f has the property that, for all x, 5f(x) = f(5x). If f(20) = 40, what is the value of f(4)?
Arada [10]

Answer:

8

Explanation:

5x=40

5 0
2 years ago
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