There are 32 more pupils in the Robotics Club than in the Art Club. The number of pupils in the Robotics Club is 18 less than 3
1 answer:
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We have that
f(x)=(x-4)^2-1 in the question and f(x)=-(x-4)^2-1 in the picture
<span>so
</span><span>I'm going to analyze the two cases
</span><span>
using a graph tool
case 1)
</span>f(x)=(x-4)^2-1<span>
the vertex is the point (4,-1)
the x intercepts are the points (3,0) and (5,0)
the y intercept is the point (0,15)
</span><span>the axis of symmetry is x=4
</span>see the attached figure N 1
case 2)
f(x)=-(x-4)^2-1
the vertex is the point (4,-1)
there is no x intercepts
the y intercept is the point (0,-17)
the axis of symmetry is x=4
see the attached figure N 2
the answer
<span>considering the case N 2 </span>is
vertex (4,-1)------> is correct
y intercept (0,-17)-----> is correct
axis of symmetry x=4-----> is correct
f(x)=(x-4)^2-1 in the question and f(x)=-(x-4)^2-1 in the picture
<span>so
</span><span>I'm going to analyze the two cases
</span><span>
using a graph tool
case 1)
</span>f(x)=(x-4)^2-1<span>
the vertex is the point (4,-1)
the x intercepts are the points (3,0) and (5,0)
the y intercept is the point (0,15)
</span><span>the axis of symmetry is x=4
</span>see the attached figure N 1
case 2)
f(x)=-(x-4)^2-1
the vertex is the point (4,-1)
there is no x intercepts
the y intercept is the point (0,-17)
the axis of symmetry is x=4
see the attached figure N 2
the answer
<span>considering the case N 2 </span>is
vertex (4,-1)------> is correct
y intercept (0,-17)-----> is correct
axis of symmetry x=4-----> is correct
Answer:
x=-6 is an extraneous solution
Step-by-step explanation:
we have
squared both sides
solve the quadratic equation by graphing
The solution is x=-6 and x=-1
see the attached figure
<u><em>Verify each solution</em></u>
substitute the value of x in the original expression
For x=-6
----> is not true
so
Is an extraneous solution
For x=-1
----> is true
so
Is the solution
