Answer:
1) (2,1) 2) D=(2, -2) 3) (-5,-5) 4) (-1,-1)
Step-by-step explanation:
1) What are the coordinates of vertex D? Since it's a square, a regular quadrilateral, the legs have the same length: A(2,5) B(6,5) = |2-6|=|-4|=4 units According to the graph D has to be located 4 units to the left.
A(2, 5); B(6, 5); C(6, 1)
D=C(6-4,1) D = (2,1)
2) A(2, 3), B(7, 3), and C(7, -2) are three vertices of square ABCD. What are the coordinates of vertex D?
The same principle, for finding this Vertex coordinate so A(2, 3), B(7, 3), and C(7, -2) leg whose measure is equal to 5 units so D, according to the graph must be 5 units to the left.
A(2, 3), B(7, 3) |2-7|=|-5|=5 units
D =C(7-5,-2) D=(2, -2)
3) A(-5, -1), B(1, -1), and C(1, -5) are three vertices of rectangle ABCD. What are the coordinates of vertex D?
In this one, we have a rectangle, the distance AB= A(-5,-1) and B(1,-1) since A and B are on the same line, we can simply calculate the absolute value of x-coordinate =|-5-1|=|-6|=6 units. According to coordinate D, can only be to the left so
So D = C(1-6,-5)
D=(-5,-5)
4) A(-1, 4), B(7, 4), and C(7, -1) are three vertices of rectangle ABCD. What are the coordinates of vertex D?
Similarly to the previous one:
A(-1,4) and B(7,4) = |-1-7|=|-8|=8
D = C(7-8,-1)
D=(-1,-1)