Question

Rain which falls onto a flat rectangular surface of length 6 m and width 4 m is collected in a cylinder of internal radius 20 cm. What is the depth of water in the cylinder after a storm in which 1 cm of rain fell? ​

Answer 1

Answer:

• 1.91 m

Step-by-step explanation:

The volume of water collected:

• V = lwh
• V = 6 m * 4m * 1 cm = 600* 400* 1 cm³ = 240000 cm³

Volume of cylinder:

• V = πr²h

We have the values of V and r, find the value of h:

• h = V/πr²
• h = 240000 /(3.14*20²) = 191 cm = 1.91 m

Answer 2

$\large\pink{\sf{Given:-}}$

• Length = 6m
• Width = 4m
• Height = 1cm
• Internal Radius of cylinder = 20 cm

$\large\purple{\sf{Solution:-}}$

$\tt \: volume = length \times width \times height$

$\tt \: volume = 6 \times 4 \times 1$

$\tt \: volume = 24m ^{3}$

Volume of water in cylindrical vessel;

$\sf\pi \: r ^{2} h$

• r = 20
• h = ?
• π = 22/7

$\sf \: h = \frac{volume}{\pi r^{2} }$

$\sf \: h = \frac{24 \times 7}{22 \times 20 \times 20}$

$\sf \: h = 0.190 \: cm$

Therefore, The height of cylinder will be 0.190 I'm approximately...