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aleksandrvk [35]

3 years ago

5

What is the approximate area of the circle, in square centimeters? Use 3.14 for π (pi). Record your answer on the grid. then fil

l in the bubbles.

2 answers:

Colt1911 [192]3 years ago

6 0

100pie or about 314 hope this helps

iragen [17]3 years ago

4 0

92 ……0.00.0.0.0.0.00..00.0.0.0. Hours

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Anna11 [10]

im sorry but i dont know

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3 years ago

Compare.Write <,>,or = 25 lb____ 384 oz

raketka [301]

25 lb > 384 oz because 25 pounds is 400 ounces.

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3 years ago

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Seven subtracted from three times a number is -4

Fynjy0 [20]

X - the number

3x - 7 = -4 |add 7 to both sides

3x = 3 |divide both sides by 3

x = 1

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3 years ago

Given the position of the particle, what the position(s) of the particle when it’s at rest

choli [55]

The position function of a particle is given by:

$X\mleft(t\mright)=\frac{2}{3}t^3-\frac{9}{2}t^2-18t$

The velocity function is the derivative of the position:

$\begin{gathered} V(t)=\frac{2}{3}(3t^2)-\frac{9}{2}(2t)-18 \\ \text{Simplifying:} \\ V(t)=2t^2-9t-18 \end{gathered}$

The particle will be at rest when the velocity is 0, thus we solve the equation:

$2t^2-9t-18=0$

The coefficients of this equation are: a = 2, b = -9, c = -18

Solve by using the formula:

$t=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}$

Substituting:

$\begin{gathered} t=\frac{9\pm\sqrt[]{81-4(2)(-18)}}{2(2)} \\ t=\frac{9\pm\sqrt[]{81+144}}{4} \\ t=\frac{9\pm\sqrt[]{225}}{4} \\ t=\frac{9\pm15}{4} \end{gathered}$

We have two possible answers:

$\begin{gathered} t=\frac{9+15}{4}=6 \\ t=\frac{9-15}{4}=-\frac{3}{2} \end{gathered}$

We only accept the positive answer because the time cannot be negative.

Now calculate the position for t = 6:

$undefined$

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2 years ago

Factor pairs for 18 and

Solnce55 [7]

3,3,2 these are the primes of 18

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4 years ago