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3 years ago

12

PLEASE HELP ME! IT A TEST AND THE TEACHER WAITING ON ME!! I NEED ANSWERS QUICK I HAVE 5 PICTURES SO LOOK PLEASE TECHNOLOGY HISTO

RY PLEASE GIVE ME RIGHT ANSWERS I'M FAILING HIS CLASS

1 answer:

Helga [31]3 years ago

7 0

Answer:

the only one that i know is skill that is D Something you have already developed

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Arturo is driving at a speed of 50 miles per hour. At 2:00 he

amid [387]

Answer:

Your answer is 37

Step-by-step explanation:

Caanan is 62 miles away and since he drives at 50 miles per hour, and if it is 2:30 then 30 minutes is half a hour, which means you divide 50 in half by 2 and get 25. After you do that then you subtract 62 and 25 to get your answer 37. Have a good day!!! :)

8 0

3 years ago

Given a 10 foot length of tree trunk with a radius of 3 feet, what is the weight of the tree trunk section if it has a density o

Nutka1998 [239]

treat the tree trunk as a cylinder

v= pi x r^2 x h

using 3.14 for pi

3.14 x 3^2 x 10 = 282.6 cubic feet

282.6 * 45 = 12, 717 pounds

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3 years ago

Can someone plz help?

vagabundo [1.1K]

your answer is C. substraction

4 0

3 years ago

At noon, ship A is 130 km west of ship B. Ship A is sailing east at 25 km/h and ship B is sailing north at 20 km/h. How fast is

Hitman42 [59]

Answer:

answer = 12.87 km/h

Step-by-step explanation:

Given

Ship A is sailing east at 25 km/h = $\frac{dx}{dt}$

ship B is sailing north at 20 km/h = $\frac{dy}{dt}$

here x and y are the sailing at t = 4 : 00 pm for ship A and B respectively

so we get x = 4 ×25 =100 km/h

y = 4× 20 = 80 km/h

let z is the distance between the ships, we need to find $\frac{dz}{dt}$ at t = 4 hr

At noon, ship A is 130 km west of ship B (12:00 pm)

so equation will be

$z^2 = (130-x)^2 + y^2......................(i)\\put x = 100 and y = 80 \\\\we | | get \\$

$z^2 = 30^2 + 80^2\\z =\sqrt{7300} km/h$

derivative first equation w . r. to t we get

$2z\frac{dz}{dt} =$ $-2(130-x)\frac{dx}{dt}$ $+2y\frac{dy}{dt}$

$\frac{dz}{dt} =\frac{1}{z}[(x -130)\frac{dx}{dt} +y\frac{dy}{dt}]$

$\frac{dz}{dt} = \frac{( -20\times25 + 80\times20)}{\sqrt{7300} }$

$= \frac{1100}{85.44}\\ = 12.87km/h$

8 0

3 years ago

right three million, eight hundred sixty-two thousand, seven hundred ninety-five standard: and expanded:

harina [27]

Answer:

Expanded: 3,000,000- 800,000- 60,000- 2,000- 700- 90- 5

Standard: 386,2795

Hope this helps!!

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3 years ago