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3 years ago

Please I really need help!

Mathematics

1 answer:

emmasim [6.3K]3 years ago

6 0

Answer: It is D

Step-by-step explanation:

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Nicholas is currently in eighth grade and intends to attend a state college when he finishes high school. Nicholas’s parents cur

Juliette [100K]

Answer:

20,814.00

これがお役に立てば幸いです。また、良い一日をお過ごしください

7 0

3 years ago

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1) Given a (x) =6x+2 and b (x) = -8x -11

Elenna [48]

I hope this helps you

8 0

4 years ago

Determine the commutators of the operators a and a+,where a = (x + ip)/2 ^1/2 and a+ = (x - ip)/ 2 ^1/2

Vsevolod [243]

Answer:

Given that:

$a = (\frac{x+ip}{2})^{\frac{1}{2}}$ and $a+= (\frac{x-ip}{2})^{\frac{1}{2}}$

if a , a+ commutator, it obeys $aa^+ = a^+a$

First find:

$aa^+ = (\frac{x+ip}{2})^{\frac{1}{2}} (\frac{x-ip}{2})^{\frac{1}{2}}$

= $(\frac{(x)^2-(ip)^2}{4})^{\frac{1}{2}}=(\frac{(x)^2+(p)^2}{4})^{\frac{1}{2}}$

Now;

$a^+a =(\frac{x-ip}{2})^{\frac{1}{2}} (\frac{x+ip}{2})^{\frac{1}{2}} = (\frac{(x)^2-(ip)^2}{4})^{\frac{1}{2}}$

= $(\frac{(x)^2-(ip)^2}{4})^{\frac{1}{2}}=(\frac{(x)^2+(p)^2}{4})^{\frac{1}{2}}$

therefore, $aa^+ = a^+a$ which implies the operators a and a+ are commutators.

7 0

3 years ago

Please Help. 25 points. <br>

vodomira [7]

Answer:

$\boxed{x = 7, y = 9, z = 68}$

Step-by-step explanation:

We must develop three equations in three unknowns.

I will use these three:

$\begin{array}{lrcll}(1) & 8x + 13y +7 & = & 180 & \\(2)& 9x - 7 + 13y +7 & = & 180 & \\(3)& 8x + 5y - 11 + z & = & 180 &\text{We can rearrange these to get:}\\(4)& 8x + 13y & = & 173 &\\(5) & 9x + 13y & = & 180 & \\(6)& 8x + 5y + z & = & 169 & \\(7)& x & = & \mathbf{7} & \text{Subtracted (4) from (5)} \\\end{array}$

$\begin{array}{lrcll}& 8(7) + 13y & = & 173 & \text{Substituted (7) into (4)} \\& 56 + 13y & = & 173 & \text{Simplified} \\& 13y & = & 117 & \text{Subtracted 56 from each side} \\(8)& y & =& \mathbf{9}&\text{Divided each side by 13}\\& 8(7) + 5(9) + z & = & 169 & \text{Substituted (8) and (7) into (6)} \\& 56 + 45 + z& = & 169 & \text{Simplified} \\& 101 + z& = & 169 & \text{Simplified} \\&z& = & \mathbf{68} & \text{Subtracted 101 from each side}\\\end{array}$

$\boxed{\mathbf{ x = 7, y = 9, z = 68}}$

4 0

3 years ago

If f(x) =4x-2 and g(x) =2x+8, what is h (x) when h (x) =f (x) +g(x)

melisa1 [442]

Answer:

h(x)=4x_2+2x+8

h(x)=6x+6

8 0

3 years ago

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