The residuals are the numbers shown next to each black line. Just total them:
15 + 10 + 11-10 +9 +10 +3-17-12 = 19.
The answer is B. 19
Given that a flyer begins from earth and thrown up with a velocity of 30 ft/sec vertically.
u = initial velocity = 30 : a = -g = 32 ft/sec^2
s(0) =initial height =4 ft.
We have the equation
where u = initial velocity : v= final velocity : s = distance travelled and a = acceleration. Here final velocity is found out as follows
Substitute to get
Since v cannot be negative, the flyer’s center of gravity cannot ever reach 20 feet.
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To reach 25 ft, put s = 25
and v must be atleast 0
Then we have
Hence if thrown with initial velocity of 40 ft /sec, it will reach a height of 25 ft.
Answer:
28.8 ft
Step-by-step explanation:
SOH CAH TOA reminds you that ...
Tan = Opposite/Adjacent
The height to the top of the antenna is opposite the angle of elevation, and the distance to the building is adjacent. So, we have ...
tan(58°) = (160 ft +antenna height)/(118 ft)
(118 ft)·tan(58°) = 160 ft + antenna height . . . . . . . multiply by 118 ft
188.8 ft - 160 ft = antenna height = 28.8 ft . . . . . . subtract 160 ft, evaluate
The height of the antenna is 28.8 ft above the top of the building. (The total height of building + antenna is 188.8 ft.)
Answer:
12
Step-by-step explanation:
.075 will be written as 75/1,000. The fraction can then be simplified to the fraction 3/40.