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3 years ago

What part of the electromagnetic spectrum that is necessary for the sense of sight in humans?

Physics

2 answers:

soldier1979 [14.2K]3 years ago

8 0

Answer: The correct answer is Visible light.

Explanation: Hope this helps and have a great day :)

Alekssandra [29.7K]3 years ago

4 0

The part of the electromagnetic spectrum that is necessary for the sense of sight in humans is called visible light. This portion of the electromagnetic spectrum is composed of the various colors that the human eyes can distinguish. Each color has a corresponding wavelength. The human eyes can see wavelengths between 390-700 nm, and visible light ranges from 380-750 nm.

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A 1 kg object sits on the earth’s surface. What is the force of gravity between the object and the earth? (mass of the earth = 5

Neporo4naja [7]

Answer:

Explanation:

6kseld;r78t0gvyu79bmkp,l[;.l,kjmnhbgyvft bujhnkmlokjnhiubgyfv vaxjosnihdfbamlskjfdnh

8 0

3 years ago

Why is velocity and not just speed important to these pilots?

horrorfan [7]

We're not sure which pilots you're talking about, but we can be sure
that whichever ones they are, velocity is more important to them than
just plain speed is.

Velocity is speed AND its direction. I can clearly recall that when I was
taking flying lessons, and later flying solo with nobody else in the airplane
to get me out of a jam, it was not enough to know that my airspeed was
90 miles per hour. I also needed to know at ALL times that my velocity
was NOT pointed straight at the ground.

Happily, I knew, even back then, the difference between velocity and
just-plain-speed, and I'm sure that that is a big part of the reason that
I am here today to tell you the tale.

6 0

3 years ago

in a two-body collision, a. momentum is always conserved. b. kinetic energy is always conserved. c. neither momentum nor kinetic

tatiyna

The answer is neither the momentum nor kinetic energy is conserved

4 0

3 years ago

Read 2 more answers

The velocity time graph of an object is shown below. How far does the object travel in the time interval t =4 s to t = 6 s?

Trava [24]

The distance covered by the object between t =4 s and t = 6 s is 4 m

Explanation:

In a velocity-time graph, the distance covered by the object represented can be found by calculating the area under the curve.

Therefore, the distance covered by the object between t = 4 s and t = 6 s is the area under the curve between 4 s and 6 s.

We see that we have to calculate the area of a triangle, with:

Base:

$b=6-4 = 2$

And height:

$h=4-0 = 4$

Therefore, the area is

$A=\frac{1}{2}bh=\frac{1}{2}(2)(4)=4$

So, the distance covered by the object is 4 m.

Learn more about distance:

brainly.com/question/3969582

#LearnwithBrainly

3 0

3 years ago

A 1232 kg car moving north at 25.6 m/s collides with a 2028 kg car moving north at 17.5 m/s . They stick together. In what direc

Citrus2011 [14]

Answer:

I. Angle = 41.7° Northeast.

II. Vr = 7.08m/s

Explanation:

Let the two cars be denoted by A and B

Given the following data;

Mass of car A = 1232 Kg

Velocity of car A = 25.6 m/s

Mass of car B = 2028 Kg

Velocity of car B = 17.5m/s

First of all, we would solve for momentum;

Momentum = mass × velocity

Momentum, M1 = 1232 × 25.6

Momentum, M1 = 31539.2 Kgm/s

Momentum, M2 = 2028 × 17.5

Momentum, M2 = 35490 Kgm/s

Now, let's find the resultant momentum using the Pythagoras theorem;

R² = M1² + M2²

R² = 31539.2² + 35490²

R² = 994721136.6 + 1259540100

R² = 2254261237

Taking the square root of both sides, we have

Resultant momentum, R = 47479.06 Kgm/s

To find the direction;

Angle = tan¯¹(M1/M2)

Angle = tan¯¹(31539.2/35490)

Angle = tan¯¹(0.89)

Angle = 41.7° Northeast.

To find the speed;

R = (M1 + M2)Vr

47479.06 = (31539.2 + 35490)Vr

47479.06 = 67029.2Vr

Vr = 47479.06/67029.2

Vr = 7.08m/s

6 0

3 years ago