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Margaret [11]
3 years ago
5

Use the formula t = (0.25) s1/2 to find the time t in seconds it will take a stone to drop a distance s of 200 feet. Round your

answer to the nearest tenth of a second.
Physics
1 answer:
blondinia [14]3 years ago
4 0

Answer:

Time taken, t = 3.53 seconds

Explanation:

It is given that,

The formula for calculating the time t is given by :

t=(0.25)s^{1/2}...... (1)

Where

s is the distance in feets

We need to find the time taken by the stone to drop a distance of 200 feets, s = 200 feets

Put the value of s in equation (1) such that,

t=(0.25)\times (200)^{1/2}

t = 3.53 seconds

So, the time taken by the object is 3.53 seconds. Hence, this is the required solution.

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The SI unit of mass is kilogram (kg)....

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3 years ago
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a net force of 100 newton’s is a moving mass with an acceleration of 5 m/s. what is the mass of the object?
Jlenok [28]

F = ma

100 N= m . 5 ms⁻¹

100 / 5 = m

20 N ms = mass of object.

7 0
3 years ago
Describe the energy transfers of an electron around a circuit when the switch is closed
motikmotik

Answer:

When a switch is closed, electrons move through a circuit from the negative side of a battery to the positive side

Explanation:

Note that current is marked to flow from positive to negative on circuit diagrams, but that's for historical reasons only. Benjamin Franklin did a fabulous job of understanding what was going on, but no one yet knew about protons & electrons, so he assumed current was flowing from positive to negative.

However, what really happens is electrons flow from negative (where they repel each other) to positive (where they are attracted).

As electrons flow through a circuit, they need 'something to do'. In many cases, that something is to light a bulb or heat an element, such as an element on a stove. So, the energy of an electron can be converted to heat or light.

I hope I'm understanding your question correctly

6 0
4 years ago
A 3.0 kg ball is lifted two meters upward in two seconds, and a 6.0 kg ball is lifted one meter upward in one second? Which requ
Sav [38]

Answer:

1. They both uses same energy

2. The 6 kg ball requires more power than 3kg ball

Explanation:

Sample 1

m = 3kg

g= 10m/s^2

h = 2m

t = 2secs

W = mgh = 3 x 10 x 2 = 60J

P= w/t = 60/2 = 30watts

Sample 2

m = 6kg

g= 10m/s^2

h = 1m

t = 1sec

W = mgh = 6 x 10 x 1 = 60J

P= w/t = 60/1 = 60watts

They both uses same energy but different power. The 6 kg ball requires more power than 3kg ball

3 0
4 years ago
The work done by an external force to move a -6.70 μc charge from point a to point b is 1.20×10−3 j .
ASHA 777 [7]

Answer:

108.7 V

Explanation:

Two forces are acting on the particle:

- The external force, whose work is W=1.20 \cdot 10^{-3}J

- The force of the electric field, whose work is equal to the change in electric potential energy of the charge: W_e=q\Delta V

where

q is the charge

\Delta V is the potential difference

The variation of kinetic energy of the charge is equal to the sum of the work done by the two forces:

K_f - K_i = W + W_e = W+q\Delta V

and since the charge starts from rest, K_i = 0, so the formula becomes

K_f = W+q\Delta V

In this problem, we have

W=1.20 \cdot 10^{-3}J is the work done by the external force

q=-6.70 \mu C=-6.7\cdot 10^{-6}C is the charge

K_f = 4.72\cdot 10^{-4}J is the final kinetic energy

Solving the formula for \Delta V, we find

\Delta V=\frac{K_f-W}{q}=\frac{4.72\cdot 10^{-4}J-1.2\cdot 10^{-3} J}{-6.7\cdot 10^{-6}C}=108.7 V

4 0
3 years ago
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