1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
algol [13]
2 years ago
9

Can someone help me please?

Mathematics
2 answers:
FromTheMoon [43]2 years ago
8 0

It seems that the square has 100 small squares in total. Out of those small squares, 64 are green.

64/100 = 0.64

Alina [70]2 years ago
4 0

Answer:

64/100 or 0.64 :)

Step-by-step explanation:

You might be interested in
Airline passengers arrive randomly and independently at the passenger-screening facility at a major international airport. The m
Elenna [48]

Answer:

Part a: <em>The probability of no arrivals in a one-minute period is 0.000045.</em>

Part b: <em>The probability of three or fewer passengers arrive in a one-minute period is 0.0103.</em>

Part c: <em>The probability of no arrivals in a 15-second is 0.0821.</em>

Part d: <em>The probability of at least one arrival in a 15-second period​ is 0.9179.</em>

Step-by-step explanation:

Airline passengers are arriving at an airport independently. The mean arrival rate is 10 passengers per minute. Consider the random variable X to represent the number of passengers arriving per minute. The random variable X follows a Poisson distribution. That is,

X \sim {\rm{Poisson}}\left( {\lambda = 10} \right)

The probability mass function of X can be written as,

P\left( {X = x} \right) = \frac{{{e^{ - \lambda }}{\lambda ^x}}}{{x!}};x = 0,1,2, \ldots

Substitute the value of λ=10 in the formula as,

P\left( {X = x} \right) = \frac{{{e^{ - \lambda }}{{\left( {10} \right)}^x}}}{{x!}}

​Part a:

The probability that there are no arrivals in one minute is calculated by substituting x = 0 in the formula as,

\begin{array}{c}\\P\left( {X = 0} \right) = \frac{{{e^{ - 10}}{{\left( {10} \right)}^0}}}{{0!}}\\\\ = {e^{ - 10}}\\\\ = 0.000045\\\end{array}

<em>The probability of no arrivals in a one-minute period is 0.000045.</em>

Part b:

The probability mass function of X can be written as,

P\left( {X = x} \right) = \frac{{{e^{ - \lambda }}{\lambda ^x}}}{{x!}};x = 0,1,2, \ldots

The probability of the arrival of three or fewer passengers in one minute is calculated by substituting \lambda = 10λ=10 and x = 0,1,2,3x=0,1,2,3 in the formula as,

\begin{array}{c}\\P\left( {X \le 3} \right) = \sum\limits_{x = 0}^3 {\frac{{{e^{ - \lambda }}{\lambda ^x}}}{{x!}}} \\\\ = \frac{{{e^{ - 10}}{{\left( {10} \right)}^0}}}{{0!}} + \frac{{{e^{ - 10}}{{\left( {10} \right)}^1}}}{{1!}} + \frac{{{e^{ - 10}}{{\left( {10} \right)}^2}}}{{2!}} + \frac{{{e^{ - 10}}{{\left( {10} \right)}^3}}}{{3!}}\\\\ = 0.000045 + 0.00045 + 0.00227 + 0.00756\\\\ = 0.0103\\\end{array}

<em>The probability of three or fewer passengers arrive in a one-minute period is 0.0103.</em>

Part c:

Consider the random variable Y to denote the passengers arriving in 15 seconds. This means that the random variable Y can be defined as \frac{X}{4}

\begin{array}{c}\\E\left( Y \right) = E\left( {\frac{X}{4}} \right)\\\\ = \frac{1}{4} \times 10\\\\ = 2.5\\\end{array}

That is,

Y\sim {\rm{Poisson}}\left( {\lambda = 2.5} \right)

So, the probability mass function of Y is,

P\left( {Y = y} \right) = \frac{{{e^{ - \lambda }}{\lambda ^y}}}{{y!}};x = 0,1,2, \ldots

The probability that there are no arrivals in the 15-second period can be calculated by substituting the value of (λ=2.5) and y as 0 as:

\begin{array}{c}\\P\left( {X = 0} \right) = \frac{{{e^{ - 2.5}} \times {{2.5}^0}}}{{0!}}\\\\ = {e^{ - 2.5}}\\\\ = 0.0821\\\end{array}

<em>The probability of no arrivals in a 15-second is 0.0821.</em>

Part d:  

The probability that there is at least one arrival in a 15-second period is calculated as,

\begin{array}{c}\\P\left( {X \ge 1} \right) = 1 - P\left( {X < 1} \right)\\\\ = 1 - P\left( {X = 0} \right)\\\\ = 1 - \frac{{{e^{ - 2.5}} \times {{2.5}^0}}}{{0!}}\\\\ = 1 - {e^{ - 2.5}}\\\end{array}

            \begin{array}{c}\\ = 1 - 0.082\\\\ = 0.9179\\\end{array}

<em>The probability of at least one arrival in a 15-second period​ is 0.9179.</em>

​

​

7 0
3 years ago
Katoni bought 2 1/2 dozen pencils . There are 12 pencils in a dozen. How many pencils did Katoni buy?
sergeinik [125]
Half of a dozen is 6. And 12+12 is 24 and 24+6 is 30. So Katoni bought 30 pencils.
5 0
3 years ago
What is the awnser.i don't get it.
Dennis_Churaev [7]
8x+Y=-16
answer
Y=-8x-16
6 0
3 years ago
Read 2 more answers
Is 1,000 a rational number or a irrational or is it a whole number ?
ad-work [718]

Answer:

1,000 is both a rational number and a whole number.

If my answer helped, please mark me as the brainliest!!

Thank You!!

3 0
3 years ago
Which of the following is a repeating decimal when converted to decimal form?
Agata [3.3K]
I believe the answer is 1/3
7 0
3 years ago
Other questions:
  • 8/7 + 7/7 = ? Help please ?
    11·2 answers
  • Area of 15 multiplied by 7.6
    11·1 answer
  • Six million three thousand twenty-one
    10·2 answers
  • A balloon is 300 feet above a cliff. The angle of depression to the cliff edge is 40° 30'. What is the horizontal distance from
    12·1 answer
  • when oxygen reacts with hydrogen it has the capacity to release 29 kilojoules of energy. Inside a fuel cell, oxygen reacts with
    10·1 answer
  • A man invested 800.00in a bank at a simple interest rate of 5% per annum .Find his total amou year​
    9·1 answer
  • PLEASE HELP I WILL GIVE BRAINLIEST!!
    11·1 answer
  • The Steelers have won 6 out of their 8
    13·1 answer
  • The water was pumped out of a backyard pond. What is the domain of this graph?
    13·1 answer
  • A rubber ball is bounced from a height of 9 meters and bounces continuously .Each successive bounce reaches a height that is a t
    14·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!