We have

In order to obtain easily the table, we need to clear y

then we evaluate for values of x
if x=0
y=-4(0)+1=1
y=1
if x=1
y=-4(1)+1=-3
y=3
if x=2
y=-4(2)+1=-7
y=-7
if x=3
y=-4(3)+1=-11
y=-11
So the table for the given equation is
x y
0 1
1 -3
2 -7
3 -11
Answer:
The slope is 8 and the y intercept is 0
Step-by-step explanation:
The equation is written in slope intercept form
y = mx+b where m is the slope and b is the y intercept
y = 8x+0
The slope is 8 and the y intercept is 0
3.04 , 3.14 , 3.4 , 4.03 , 4.4
Answer:
1.5
Step-by-step explanation:
45 divided by 30 = 1.5
Hope this helps
Answer:
She increased 80% the practise time
Step-by-step explanation:
The question is incomplete, the following is missing:
<em>by how much did she increase the time she practised each day?
</em>
From Monday to Wednesday she increased 90 - 50 = 40 minutes the practise time.
To compute the increment as a percentage use: increment/reference *100
In this case, that is: 40/50*100 = 80%, where 50 minutes is taken as a reference.