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2 years ago

Which of the graphs best represents a system of equations that has no solution?

Mathematics

1 answer:

Lesechka [4]2 years ago

3 0

When the lines are parallel then there is no solution to the system of equations.
This happens because the intersection is the solution. And when there is no intersection then there is no solution.

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PLZ ANSWER Selena picked eight baskets of tomatoes. Her sister threw away one of the baskets due to bruising. What percent were

I am Lyosha [343]

Answer

12.5 percent was bad, 87.5 were good

Step-by-step explanation:

set up this percentage solver $\frac{1}{8} *\frac{x}{100}$

then cross multiply

$8x=100$

divide by eight

12.5 were bad

so 87.5 were good

7 0

2 years ago

Read 2 more answers

I NEED IT EXTREMELY FAST!!!!

pochemuha

Answer:

x = 11 | Scale factor = 2

Step-by-step explanation:

As you can see, the 3 turns into a six meaning it multiplied by 2. Apply this to 5.5 to get 11. The 2 is your scale factor.

Hope this helps,

If you like my answer please give brainliest

Happy Holidays to everyone!

6 0

2 years ago

Read 2 more answers

QUESTION 3

eduard

Athe answer is -2 because it is behind the 0 and will be negative and it is two lines away from the 0 so the answer is -2

3 0

3 years ago

Jared bought a Suzuki 1000 for $12,698. If it depreciates at a rate of 11% per year, how much will it be worth in 3 years

Serga [27]

Original price = P = $12,698
Depreciation rate = r = 11% = 0.11
Time in years = t = 3
New price = A

The formula used will be:

$A=P(1-r)^{t}$

Using the values, we get:

$A=12698(1-0.11)^{3}=8951.70$

Thus, the worth of Suzuki after 3 years will be $8951.70

7 0

2 years ago

Write the equation of a line Parallel to the given line and passes through points (-4, -3); (2, 3). Hints find the slope by usin

julia-pushkina [17]

First, we obtain the gradient (slope) of the first parallel line

$\text{gradient, m}_1\text{ = }\frac{y_2-y_1}{x_2-x_1}\text{ = }\frac{3-(-3)}{2-(-4)}=\frac{6}{6}\text{ = 1}$

Recall that since both lines are parallel, we have that,

$m_1=m_2$

Thus

$m_2\text{ = 1}$

Hence, we can find the equation of the parallel line given that it passes through the points (-4, -3)

Using

$\begin{gathered} y\text{ = mx + c} \\ \text{where m = m}_2\text{ = 1} \\ \text{and x = -4 , y = -3, we have} \\ -3\text{ = 1(-4) + c} \\ -3\text{ = -4 + c} \\ 4\text{ - 3 = c} \\ c\text{ = 1} \\ \text{Thus, the equation of the line is y = (1)x + 1} \\ y\text{ = x + 1} \end{gathered}$

5 0

1 year ago