2 years ago

Jake took 4 piano lessons last month. For each lesson, he memorized 2 major scales and x minor scales.

Mathematics

1 answer:

DerKrebs [107]2 years ago

6 0

b and c are the answers i think....

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In order to estimate the average time spent on the computer terminals per student at a local university, data were collected fro

VladimirAG [237]

Answer:

Margin of error for a 95% of confidence intervals is 0.261

Step-by-step explanation:

Step1:-

Sample n = 81 business students over a one-week period.

Given the population standard deviation is 1.2 hours

Confidence level of significance = 0.95

Zₐ = 1.96

Margin of error (M.E) = $\frac{Z_{\alpha }S.D }{\sqrt{n} }$

Given n=81 , σ =1.2 and Zₐ = 1.96

Step2:-

 $Margin of error (M.E) = \frac{Z_{\alpha }S.D }{\sqrt{n} }$ 

 $Margin of error (M.E) = \frac{1.96(1.2) }{\sqrt{81} }$ 

On calculating , we get

Margin of error = 0.261

Conclusion:-

Margin of error for a 95% of confidence intervals is 0.261

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3 years ago

Simplify the expression x8 y-26/x14 y-5 X x-39 y-21.

KonstantinChe [14]

$\frac{x^8y^{-26}}{x^{14}y^{-5}}[x^{-36}y^{-21}]$

We will apply these following power rule

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$x^m/x^n=x^{m-n}$

$[ \frac{x^8}{x^{14}}][ \frac{y^{-26}}{y^{-5}}][x^{-39}y^{-21}]$
$[x^{8-14}][y^{-26-5}][x^{-39}y^{-21}]$
$x^{-6}y^{-21}[x^{-39}y^{-21}]$
$[x^{-6-39}][y^{-21-21}]$
$x^{-45}y^{-42}$

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Download connects Q&A they have the answers on there

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777dan777 [17]

Answer:g/c

Step-by-step explanation:

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