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ELEN [110]
3 years ago
6

66 is 3/4 of what number

Mathematics
1 answer:
Anarel [89]3 years ago
3 0

Answer:88

Step-by-step explanation:

Divide 66 by 3 (66/3)

Then you should get 22

Multiply 22 by 4 (22 x 4)

Answer: 88

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2x + 5y = 10<br>5y<br>x +<br>2.<br>+<br>= 4​
elena-s [515]
Could you attach photo of a problem. It appears 2+..... =4 is missing
4 0
3 years ago
What is the value of -44
garik1379 [7]
Hi friend!


I presume you mean "What is the absolute value of -44!

Well an absolute value is always positive. So the absolute value of -44 is 44!


Hope I helped!


If not, tell me more clearly what you need!
4 0
3 years ago
Read 2 more answers
HELP PLEASE laws of sines and/or cosines
Nastasia [14]

Answer:

A= 37 Degrees

C= 106 Degrees

i think this is what you need

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Si la época prehistórica sucedió desde hace 2.5 millones de años a.C., hasta hace 2.500 años a.C.; el período Paleolítico (2.5 m
tia_tia [17]

Answer:

El período paleolítico corresponde a \frac{332}{333} de la época prehistórica.

Step-by-step explanation:

En primer lugar, se determina la extensión de tiempo, medida en años, tanto de la época prehistórica como el período paleolítico: (Nótese que el signo negativo significa a.C.)

Época Prehistórica

\Delta T = -2500-(-2500000)

\Delta T = 2497500\,years

Período Paleolítico

\Delta t = -10000 - (-2500000)

\Delta t = 2490000\,years

La fracción de la época prehistórica que corresponde al período paleolítico es:

r = \frac{\Delta t}{\Delta T}

r = \frac{2490000\,years}{2497500\,years}

r = \frac{332}{333}

El período paleolítico corresponde a \frac{332}{333} de la época prehistórica.

5 0
4 years ago
You purchased a rare painting for $150 that is increasing in value by 3% annually. How many years will it take until it is doubl
Ahat [919]

Answer:

23 years.

Step-by-step explanation:

It is given that the initial price of painting is $150 and its values increasing by 3% annually.

We need to find how many years will it take until it is doubled in value.

The value of painting after t years is given by

y=150(1+0.03)^t

y=150(1.03)^t

The value of painting after double is 300. Substitute y=300.

300=150(1.03)^t

Divide both sides by 150.

2=(1.03)^t

Taking log both sides.

\log 2=\log (1.03)^t

\log 2=t\log (1.03)

t=\dfrac{\log 2}{\log (1.03)}

t=23.44977

t\approx 23

Therefore, the required number of years is 23.

6 0
3 years ago
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