7m+2=7n−5
Swap sides so that all variable terms are on the left hand side.
7n−5=7m+2
Add 5 to both sides.
7n=7m+2+5
Add 2 and 5 to get 7.
7n=7m+7
Divide both sides by 7.
7
7n
 
 = 
7
7m+7
 
 
Dividing by 7 undoes the multiplication by 7.
n= 
7
7m+7
 
 
Divide 7+7m by 7.
n=m+1
 
        
             
        
        
        
Answer:
 ℎℎ ℎ 
Step-by-step explanation:
ℎℎℎℎ ℎ <em /><em /><em /><em /><em /><em /><em /><em><u /></em><em><u /></em><em><u /></em><em><u /></em><em><u /></em><em><u> </u></em><em><u /></em><em><u /></em><em><u /></em><em><u /></em><em><u /></em><em><u> </u></em><em><u>ℎ</u></em><em><u /></em><em><u /></em><em><u /></em><em><u /></em>
 
        
             
        
        
        
Answer:
Option c, A square matrix
Step-by-step explanation:
Given system of linear equations are



Now to find the type of matrix can be formed by using this system
of equations
From the given system of linear equations we can form a matrix
Let A be a matrix
A matrix can be written by
A=co-efficient of x of 1st linear equation    co-efficient of y of 1st linear equation   constant of 1st terms linear equation
co-efficient of x of 2st linear equation   co-efficient of y of 2st linear equation  constant of 2st terms linear equation
co-efficient of x of 3st linear equation   co-efficient of y of 3st linear equation    constant of 3st terms linear equation           
which is a  matrix.
 matrix.
Therefore A can be written as
A= ![\left[\begin{array}{lll}3&-2&-2\\7&3&26\\-1&-11&46\end{array}\right] 3\times 3](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Blll%7D3%26-2%26-2%5C%5C7%263%2626%5C%5C-1%26-11%2646%5Cend%7Barray%7D%5Cright%5D%203%5Ctimes%203)
Matrix "A" is a  matrix so that it has 3 rows and 3 columns
 matrix so that it has 3 rows and 3 columns 
A square matrix has equal rows and equal columns
Since matrix "A" has equal rows and columns Therefore it must be a square matrix
Therefore the given system of linear equation forms a square matrix
 
        
                    
             
        
        
        
5(x + 27) >= 6(x + 26)
5x + 135 >= 6x + 156
-x >= 21
x <= -21
Answer: Choice B.