Question

50 POINTS

Answer 1

$\huge \sf༆ Answer ༄$

According to the question ;

${ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \:y \propto x$

Now, let's add a constant of proportionality to replace proportionality sign with equal to :

${ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \:y = kx$

[ where, k is proportionality constant ]

plug the value of x and y from any ordered pair in the table , for example : $\sf(\dfrac{1}{5} , 2)$

${ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \:2 = k \times \dfrac{1}{5}$

${ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \:k = 2 \times 5$

${ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \:k = 10$

Therefore, value of proportionality constant (k) is

$\overbrace{ \underbrace{\underline{ \boxed{ \sf 10 }}}}$