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kicyunya [14]
2 years ago
11

Andrew measured a line to be 12.2 inches long. If the actual length of the line is 12.7 inches, then what was the percent error

of the measurement, to the nearest tenth of a percent?
Mathematics
1 answer:
Brums [2.3K]2 years ago
4 0

The percent error of the measurement, to the nearest tenth of a percent is 3.9%

Given:

Length measured = 12.2 inches

Actual length = 12.7 inches

Error<em> =</em> Actual length - Length measured

= 12.7 - 12.2

= 0.5

Percentage error = error / actual value × 100

= 0.5/12.7 × 100

= 0.039370078740157 × 100

= 3.937%

Approximately,

Percentage error = 3.9%

Therefore, the percent error of the measurement, to the nearest tenth of a percent is 3.9%

Learn more about percentage error:

brainly.com/question/5493941

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Mice21 [21]

Answer:

Every angle of Square = 90°

diagonal bisects the angle in half.

=> angle FGI = 45°

=> 7x+3=45

=>7x=42

therefore, x=42/7=6

5 0
3 years ago
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At the city museum, child admission is $5.10 and adult admission is $9.60. On Monday, twice as many adult tickets as child ticke
galina1969 [7]

Answer:

23

Step-by-step explanation:

The amount of children's tickets is x, while the amount of adults' tickets is 2x

5.1*x- the amount of money from children

9.6*2x= 19.2x- the amount of money from adults

5.1x+19.2x= 558.9

x=23 - child tickets

8 0
2 years ago
Let f(x)= 7-2x Find a. f(4) b. f(h) c. f(4) + f(h) d. f(3+h)
anyanavicka [17]

Step-by-step explanation:

a) f(4) = 7-2(4)

= -1

b) f(h) = 7-2(h)

= 7-2h

c) f(4) + f(h) = -1 +(7-2h)

= 6-2h

h = 3

d) f(3+h) = 7-2(3+h)

= 7-6-2h

= -1-2h

2h= -1

h = -1/2

p/s = if the real answer is different with my answer, tell me also please. Im just a student that still learning.

4 0
2 years ago
Use the properties of logarithms to expand the following expression as much as possible. Simplify any numerical expressions that
sweet [91]

Answer:

f(x,y) = \log_{4} (x-5-\sqrt{25-6\cdot y})+\log_{4} (x-5+\sqrt{25-6\cdot y})

Step-by-step explanation:

Let be f(x,y) = \log_{4}(2\cdot x^{2}-20\cdot x +12\cdot y), this expression is simplified by algebraic and trascendental means. As first step, the second order polynomial is simplified. Its roots are determined by the Quadratic Formula, that is to say:

r_{1,2} = \frac{20\pm \sqrt{(-20)^{2}-4\cdot (2)\cdot (12\cdot y)}}{2\cdot (2)}

r_{1,2} = 5\pm \sqrt{25-6\cdot y}

The polynomial in factorized form is:

(x-5-\sqrt{25-6\cdot y})\cdot (x-5+\sqrt{25-6\cdot y})

The function can be rewritten and simplified as follows:

f(x,y) = \log_{4} [(x-5-\sqrt{25-6\cdot y})\cdot (x-5+\sqrt{25-6\cdot y})]

f(x,y) = \log_{4} (x-5-\sqrt{25-6\cdot y})+\log_{4} (x-5+\sqrt{25-6\cdot y})

3 0
3 years ago
The radius of this ball is 15 inches. Which equation gives the ball's surface area, in square inches?
victus00 [196]

Answer:

\large\boxed{S.A.=4500\pi\ in^2\approx14130\ in^2}

Step-by-step explanation:

The formula of a surface area of a ball (sphere):

S.A.=\dfrac{4}{3}\pi R^3

R - radius

We have R = 15in. Substitute:

S.A.=\dfrac{4}{3}\pi(15^3)=\dfrac{4}{3}\pi(3375)=4500\pi\ in^2

If you want to get an approximation, then:

\pi\approx3.14\\\\S.A.\approx(4500)(3.14)=14130\ in^2

5 0
2 years ago
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