QUESTION 1
When the plane reaches an altitude of 360,000 feet, the temperature outside the plane is 65 degrees below zero Fahrenheit.
This means that the temperature will be:
The temperature is -65°F.
QUESTION 2
If the temperature gets warmer by 10 degrees, this means that the new temperature will be the sum of the original temperature and 10 degrees:
The temperature is -55°F.
Answer/Step-by-step explanation:
7x- 4 = -182
<em>Step:</em>
Add 4 to both sides
7x - 4 + 4 = -182 + 4
Simplify
7x = -178
Divide both sides by 7
7x/7 = -178/7
Simplify
x = -178/7
Decimal form = -25.4285714286
<u><em>~lenvy~</em></u>
59 is D
because with the point (-3,7) you substitute it into the equation, making it: 7=4x+b. solve for b. then you have y=4x+19. work out the algebra in the possible choices and whatever equals y=4x+19 will be the answer. in this case, its D.
60 is C
same as above, you do the algebra of the equation. bring the one over after doing distribution with the 4 and voila!
61 is A
a relatively easy one, all you do is the the slope -4 where m goes, and 3 where b goes. y= -4x+3
62 is C.
this one requires more work.
chose one of the points, in this case (2,7) and put them into the equation.
but wait, you need a slope!
you get that use the formula (y2-y1)/(x2-x1) which will be
(7-5)/(2-3) which will be
-2.
now you have y-7= -2(x-2)
voila!
63 is C. y= 1/2x+3
64 is B. (3, -5)
66 is B. negative. the line goes \ ( not / which is positive)
67 would be A. because it is positive and the I and the E are in the right places.
70 is C. 2/3. as before, remember we can but the points into this equation and have (6-4)/(3-0) which = 2/3
71 is D. y= 3x+10
72 is C. a third degree monomial
73 can't read
74 can't read
75 can't read.
Weird way to write it but alright! (Sideways)
19pq^-2 x 5pq^6 = ?
These problems are pretty much single operations between each of the variables / constants.
So it's like this:
(19*5)(p*p)(q^-2*q^6) = ?
19*5 is 95.
For p*p remember that when two variables multiply there given powers add. In the case where the powers are not shown (like in the case of p*p) they are always assumed to be 1. So what is 1+1? 2.
p*p is p^2
For q^-2*q^6 it is the same deal with the previous problem. So now the problem looks like this:
-2 + 6 = 4
(The two is negative, because the power is negative 2)
So, q^4.
Our final answer is all of the combined.... like a so:
95p^2q^4
