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inn [45]
3 years ago
11

Can somebody explain it to me please?​

Physics
2 answers:
Volgvan3 years ago
6 0

Answer:

45°.

It is a property of the parabolas.. When the angle between a parabola and the x-axis is 45° the range is maximum.

Mumz [18]3 years ago
6 0

Range be R and height be h

\boxed{\sf R=\dfrac{u^2sin2\theta}{g}}

\boxed{\sf h=\dfrac{u^2sin^2\theta}{2g}}

u=initial velocity

theta is angle of projection.

g=acceleration due to gravity

ATQ

\\ \sf\longmapsto R=2h

\\ \sf\longmapsto \dfrac{u^2sin2\theta}{g}=\dfrac{2u^2sin^2\theta}{2g}

Cancelling required ones

\\ \sf\longmapsto sin^2\theta=sin2\theta

sin2O=2sinOcosO

\\ \sf\longmapsto sin^2\theta=2sin\theta cos\theta

\\ \sf\longmapsto \dfrac{sin^2\theta}{sin\theta cos\theta=2

\\ \sf\longmapsto \dfrac{sin\theta}{cos\theta}=2

\\ \sf\longmapsto tan\theta=2

\\ \sf\longmapsto \theta=tan^{-1}(2)

\\ \sf\longmapsto \theta=63.4°

Done

Option B is correct

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Your average speed on the first half of a car trip is 69.0 km/h. How fast do you have to drive on the second half of the trip to
vova2212 [387]

Answer:

13 km/h

Explanation:

Average speed = distance/time

Let the total distance and total time taken for the whole trip be d km and t hours respectively

Average speed for the whole trip = 82 km/h

d = 82t

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Time taken = t/2

Average speed = 69 km/h

69 = d1/2 ÷ t/2

d1 = 69t

The distance covered in the second half = d2/2

Time taken = t/2

Let the average sly for the see half be A

A = d2/2 ÷ t/2

d2 = At

d = d1 + d2

82t = 69t + At

At = 82t - 69t

At = 13t

A = 13t/t = 13 km/h

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4 years ago
Assume that a gravitational anomaly in the solar system has shifted a field of asteroids into Earth’s orbit, and the field is no
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7 0
2 years ago
The current in some DC circuits decays according to the function I=I0e−t/τ, where I is the current at some point in time, I0 is
almond37 [142]

Answer: 1.95

Explanation:

You should start off from the decay formula and solve for τ:

I = I_{0}e^{\frac{t}{\tau\\  } }

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Apply inverse logarithmic function:

ln(\frac{0.2 A}{1.2 A} ) = \frac{-t}{\tau}

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7 0
3 years ago
Read 2 more answers
Suppose a wheel with a tire mounted on it is rotating at the constant rate of 2.23 2.23 times a second. A tack is stuck in the t
elena-14-01-66 [18.8K]

Explanation:

The given data is as follows.

       Angular velocity (\omega) = 2.23 rps

     Distance from the center (R) = 0.379 m

First, we will convert revolutions per second into radian per second as follows.

             = 2.23 revolutions per second

             = 2.23 \times 2 \times 3.14 rad/s

             = 14.01 rad/s

Now, tangential speed will be calculated as follows.

  Tangential speed, v = R \times \omega

                               = 0.379 x 14.01

                               = 5.31 m/s

Thus, we can conclude that the tack's tangential speed is 5.31 m/s.

8 0
3 years ago
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