Well as the fish swims he pushes the water behind him which in return push him forward
Explanation:
Average power = change in energy / change in time
P = ΔE / Δt
P = (½ mv²) / t
P = (½ (0.825 kg) (0.620 m/s)²) / (0.021 s)
P = 7.55 Watts
To solve this problem it is necessary to apply the concepts related to the Third Law of Kepler.
Kepler's third law tells us that the period is defined as

The given data are given with respect to known constants, for example the mass of the sun is

The radius between the earth and the sun is given by

From the mentioned star it is known that this is 8.2 time mass of sun and it is 6.2 times the distance between earth and the sun
Therefore:


Substituting in Kepler's third law:






Therefore the period of this star is 3.8years
Force of gravity. Hope this is correct good luck!!
A tigers lost one and yyyyyyyy was the first day in a while and they didn’t have a back up 4.5 50m