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Alex17521 [72]
2 years ago
12

I need Help!!!(Question is attached)

Mathematics
1 answer:
katrin2010 [14]2 years ago
3 0

Answer:

SEE BELOW

Step-by-step explanation:

1 - 12000 ft

2 - 10 minutes

3 - The third segment in he graph is not as steep as the first segment because the flight took more time to lose altitude than the time taken to gain altitude.

<em>Hope it helped</em>

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Graph the equation below by plotting the y-intercept and a second point on the line. <br> y=3/2x-1
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The diagram of the plotting point \left(3\frac{1}{2},\:2\frac{3}{4}\right)=\left(3.5,\:2.75\right) is attached below.

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Given the points

\left(3\frac{1}{2},\:2\frac{3}{4}\right)

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so the point can be visualized as:

\left(3\frac{1}{2},\:2\frac{3}{4}\right)=\left(3.5,\:2.75\right)

Now, we can check the point x = 3.5, and determine the corresponding value y = 2.75 and plot the point at the location (x, y) = (3.5, 2.75)

The diagram of the plotting point \left(3\frac{1}{2},\:2\frac{3}{4}\right)=\left(3.5,\:2.75\right) is attached below.

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Answer:

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Wow! Thank you for an interesting question with a not-so-obvious answer.

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<em>A little more detail</em>

The point I that you have defined is the incenter—the center of an inscribed circle in the triangle. Its radius is the distance from I to any side, such as BC, for example.

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Putting these ratios and perimeters together, we get ...

... perimeter ΔAMN = (2Δ/(BC) -Δ/s)/(2Δ/(BC)) × 2s

... = (2/(BC) -1/s) × BC × s = 2s -BC

... perimeter ΔAMN = AB +AC

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