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Inga [223]
3 years ago
13

Given the following linear function sketch the graph of the function and find the domain and range f(x)=-3x+7

Mathematics
1 answer:
natka813 [3]3 years ago
6 0
<h3>Answer:</h3>

see attached for a graph

domain and range: all real numbers

<h3>Step-by-step explanation:</h3>

The function is written in slope-intercept form, showing that it has a slope of -3 and a y-intercept of +7. The y-intercept (0, 7) is a point on the line, as is a point 1 unit to the right and down 3 units, (1, 4).

The graph will be the line through these two points.

_____

As with any odd-degree polynomial function, both domain and range are all real numbers: (-∞, ∞).

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Answer:

\frac{ \frac{ \frac{5}{6} }{1} }{2}  =  \frac{5}{3}  = 1 \times \frac{2}{3}

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Caroline walked 3 miles to warm up. She then ran at a rate of 7 miles per hour. Find the total
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ABCD is a parallelogram.
kow [346]

Opposite sides of a parallelogram are equal lengths, so ...

... AB = CD

... 6x +30 = 2y -10

and

... BC = AD

... 2x -5 = y -35

_____

The equations can be put in standard form to get

... 3x -y = -20

... 2x -y = -30

Subtracting the second from the first, we get

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Solving for y, we have

... y = 2x+30 = 2·10 +30 = 50

The values of x and y are x=10, y=50.

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3 0
3 years ago
AB is tangent to circle D. Find the value of x.
Svet_ta [14]

Answer:

c     15

Step-by-step explanation:

Tangent AB is tangent to circle D at point A. The angle made by a tangent to a circle and a radius of the circle at the point of tangency is a right angle. That means that angle is a right angle, and triangle ABD is a right triangle.

We can use the Pythagoren theorem.

a^2 + b^2 = c^2

x^2 + 20^2 = (x + 10)^2

x^2 + 400 = (x + 10)(x + 10)

x^2 + 400 = x^2 + 10x + 10x + 100

400 = 20x + 100

20x = 300

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6 0
3 years ago
Help is very much needed !
vichka [17]

Answer:

1600

Step-by-step explanation:

<h3>(-2)^{4}  x (-10)^{2}[/tex]</h3><h3></h3><h3>Evaluate it: 2^{4} x -10^{2}</h3><h3>Multiply: 16x100</h3><h3>Finally you get:</h3><h3>1600</h3>
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