Given the following linear function sketch the graph of the function and find the domain and range f(x)=-3x+7
1 answer:
<h3>Answer:</h3>
see attached for a graph
domain and range: all real numbers
<h3>Step-by-step explanation:</h3>The function is written in slope-intercept form, showing that it has a slope of -3 and a y-intercept of +7. The y-intercept (0, 7) is a point on the line, as is a point 1 unit to the right and down 3 units, (1, 4).
The graph will be the line through these two points.
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As with any odd-degree polynomial function, both domain and range are all real numbers: (-∞, ∞).
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Answer:
is the required polynomial with degree 3 and p ( 7 ) = 0
Step-by-step explanation:
Given:
p ( 7 ) = 0
To Find:
p ( x ) = ?
Solution:
Given p ( 7 ) = 0 that means substituting 7 in the polynomial function will get the value of the polynomial as 0.
Therefore zero's of the polynomial is seven i.e 7
Degree : Highest raise to power in the polynomial is the degree of the polynomial
We have the identity,
Take a = x
b = 7
Substitute in the identity we get
Which is the required Polynomial function in degree 3 and if we substitute 7 in the polynomial function will get the value of the polynomial function zero.
p ( 7 ) = 7³ - 21×7² + 147×7 - 7³
p ( 7 ) = 0