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Andrew [12]
3 years ago
14

What x value sloves the equation . 3x-5=1

Mathematics
1 answer:
djyliett [7]3 years ago
8 0
3x-5=1
+5 +5
3x=6
3 3
X= 2
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12/45 =¿ fraccion mixta ,propia o impropia?<br><br> 24/5=¿fraccion mixta,propia o impropia?
Aloiza [94]
12/45 = fracción propia24/5 = fracción impropia
8 0
3 years ago
PLS help <br> 85% of 2500m
pishuonlain [190]

Answer:

2125m or 2km or 125m

Step-by-step explanation:

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3 0
2 years ago
A cube with 40-cm-long sides is sitting on the bottom of an aquarium in which the water is one meter deep. (Round your answers t
Molodets [167]

Answer:

940.8 N

1254.4 N

Step-by-step explanation:

I would think the questions would be to calculate the forces at the top of the cube and at the sides. Thus:

On the top:

F = pressure * area

P = density * gravity * height

the height would be:

1m - 0.4m = 0.6m

replacing:

P = 1000 * 9.8 * 0.6 = 5880

A = (0.4) ^ 2 = 0.16

F = 5880 * 0.16

F = 940.8 N

On the sides:

dF = d * g * h * dA

dA = 0.4 * dh replacing

dF = 1000 * 9.8 * h * 0.4 * dh

dF = 3920 * h * dh

We integrate both sides and we have:

F = 3920 * (h ^ 2/2), h = 0.6 up to h = 1

F = (3920/2) * (1 ^ 2 - 0.6 ^ 2)

F = 1254.4 N

3 0
4 years ago
Solve the system of linear equations by graphing
Eddi Din [679]

Answer:

(3,-1/2)

Step-by-step explanation:

7 0
3 years ago
The jaguars scored 37 points their first game. They scored 58 points their second game. What is their percent change?​
aliina [53]

Answer:

Change in percent = 56.75 (Approx.)

Step-by-step explanation:

Given:

Score in first game = 37 points

Score in second game = 58 points

Find:

Change in percent

Computation:

Change in percent = [(Score in second game - Score in first game)/Score in first game]100

Change in percent = [(58-37)/37]100

Change in percent = [(21)/37]100

Change in percent = 56.75 (Approx.)

7 0
3 years ago
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