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MrMuchimi
3 years ago
10

Solve the three variable system. (I was just introduced to these)

Mathematics
2 answers:
sladkih [1.3K]3 years ago
8 0
First we have to get down to a system of two equations, then we can work from there. adding the first and third equation together, we get

x - y + (y - 2z) = 2 + ( - 3) \\ x - 2z = - 1
now multiply the second equation by 2, and add it to our new equation

6x + 2z = 22 \\ 6x + 2z + (x - 2z) = 22 - 1 \\ 7x = 21 \\ x = 3

now plug x into the second equation

3(3) + z = 11

z = 2

and plug it into the first equation

3 - y = 2

y = 1
Elanso [62]3 years ago
4 0
So basically you do two of the equations first and then solve for the last equation. Please Refer To The Picture



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tangare [24]

Answer:

D. 29.75

Step-by-step explanation:

To determine the mean, you must add up all the numbers and then divide that number by how many numbers you added.

Here,

21 + 23 + 35 + 40

= 119

You added 4 numbers (21, 23, 35, 40),

so, 119 / 4

= 29.75

Hope this helps and a thank won't hurt! :)

3 0
3 years ago
Ted knows the actual distance between two cities is 150 miles. His map shows a distance of 2 inches between these cities. What i
Serjik [45]

Answer:

The scale used on his map is <u>150 miles : 2 inches</u>.

Step-by-step explanation:

Given:

Ted knows the actual distance between two cities is 150 miles. His map shows a distance of 2 inches between these cities.

Now, to find the scale Ted used on his map.

The actual distance Ted know between two cities = 150 miles.

The distance on map between these cities = 2 inches.

So, to get the scale used on his map:

\frac{The\ actual\ distance\ Ted\ know\ between\ two\ cities}{The\ distance\ on\ map\ between\ these\ cities}

=\frac{150\ miles}{2\ inches}

=150\ miles:2\ inches.

Therefore, the scale used on his map is 150 miles : 2 inches.

5 0
3 years ago
When finding the 9th term in a geometric sequence with a common ratio of 2 and a first
Zarrin [17]

Answer:

8

Step-by-step explanation:

Nth term of a geometric sequence is given as:

t_n = a r^{(n-1)} ...(1)

Plugging n = 9, a = 3 and r = 2 in the above equation, we find:

t_9 = (3) (2)^{9-1}

t_9 = (3) (2)^{8}... (2)

Comparing equations (1) & (2), we obtan:

(n - 1) = 8

5 0
3 years ago
A person breathes 2.5 x 10^-4 in about cubic meters of air per second. How long does it take to breathe in 2.5 cubic meters of a
Ipatiy [6.2K]

Answer:

10⁴ seconds

Step-by-step explanation:

Given that,

A person breathes 2.5\times 10^{-4} in about cubic meters of air per second.

We need to find time taken to breathe 2.5 cubic meters of air.

In 1 sec = 2.5\times 10^{-4} m³ of air breathe

Let in x seconds, 2.5 m³ of air taken by the person.

x=\dfrac{2.5}{2.5\times 10^{-4}}\\\\x=10^4\ s

Hence, in 10⁴ seconds 2.5 m³ of air is taken by the person.

5 0
3 years ago
Two sets are shown in the Venn diagram. Set N represents the natural numbers, and Set W represents the whole
mafiozo [28]

Answer:

In my opinion this is the whole w

Step-by-step explanation:

7 0
3 years ago
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