Answer:
Use the half angle formula, sin^2(x) = 1/2*(1 - cos(2x)) and substitute into the integral so it becomes 1/2 times the integral of (1 - cos(2x)) dx. Set u = 2x and du = 2dx to perform u substitution on the integral. Since dx = du/2, the result is 1/4 times the integral of (1 - cos(u)
Step-by-step explanation:
Have a horse-some day!
Answer:
I would love to help you but I'm only in 7thhh
If the question is Log4 (8/x)^2
Then...
Log^2 2^2 (8/x)
(1/2 Log2 (8/x))^2
1/4 Log^2 2(8/x)
(log^2 2(8/x))/4
(9-6log2 (x)+ log^2 2(x))/4