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svp [43]
2 years ago
7

How do you solve for x?

tle=" log_{6}(36) = 5x + 6" alt=" log_{6}(36) = 5x + 6" align="absmiddle" class="latex-formula">
​
Mathematics
2 answers:
Paladinen [302]2 years ago
4 0

The value of x in the given equation is -\frac{4}{5}

From the question,

We are to solve the given equation

The given equation is

log_{6}(36) = 5x +6

This becomes

log_{6}(6^{2} ) = 5x +6

From one of the laws of logarithms, we have that

log_{x}(x^{2} ) = 2log_{x}(x)

and

log_{x}(x) = 1

∴ log_{6}(6^{2} ) = 5x +6 becomes

2log_{6}(6) = 5x +6

and

2(1)= 5x +6

2 = 5x +6

Now, subtract 6 from both sides

2-6 = 5x +6-6

-4 = 5x

∴ x = -\frac{4}{5}

Hence, the value of x in the given equation is -\frac{4}{5}

Learn more on solving equations here: brainly.com/question/11802986

Julli [10]2 years ago
4 0

\huge \rm༆ Answer ༄

The value of x is ~

  • -0.8

\large \boxed{ \mathfrak{Step\:\: By\:\:Step\:\:Explanation}}

Let's solve for x ~

  • \sf \:  log_{6}(36)  = 5x + 6

  • 2 = 5x + 6

  • 5x = 2 - 6

  • x =  - 4 \div 5

  • x =  - 0.8

I hope it helped ~

꧁  \:  \large \frak{Eternal \:  Being } \: ꧂

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